The answer is A!! Your welcomeeee
Answer:
P' = (-4,2)
Q' = (-2,5)
R' = (-1,-4)
S' = (-6,-1)
Step-by-step explanation:
Answer: 
====================================================
Work Shown:


The trick here is to first simplify the expression so that the
term in the very lower denominator cancels out. This is to avoid dividing by zero. Once this division by zero error is avoided, we can replace the delta x term with 0 and evaluate the limit as
approaches 0 from the right or positive direction.
Answer:
167.27 mg.
Step-by-step explanation:
We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.
We will use half life formula to solve our given problem.
, where N(t)= Final amount after t years,
= Original amount, t/2= half life in years.
Now let us substitute our given values in half-life formula.


Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.