Mean=5
sd=2
Using Z(x)=(x-mean)/sd
Z(2)=(2-5)/2=-1.5
Z(6)=(6-5)/2=0.5
Therefore
probability of finding a spot between 2 and 6 minutes is
P(x<6)-P(x<2)
=P(Z<0.5)-P(Z<-1.5)
=0.6915-0.0668
=0.6247
=>
More than half of the students (62.5%) finds a space between 2 and 6 minutes.
The answer to the problem is. -8b*2+21b.
Answer:
The temperature on the 5th day was of -9ºC.
Step-by-step explanation:
Mean of a data-set
The mean of a data-set is the sum of all values in the data-set divided by the number of values.
The mean temperature for the first 4 days in January was 1°C.
This means that during the first 4 days, the sum of the temperatures was 4*1 = 4ºC.
The mean temperature for the first 5 days in January was -1°C.
First 4 days: Sum of 4º
5th day: Temperature of x.
The mean is -1, so:
The temperature on the 5th day was of -9ºC.
Answer:Y=30x
Step-by-step explanation:
90-0=90
9-6=3
90/3=30
y=30x