For the first question, simply find a point that is on the line segment. For the second question, knowing that in quadrant iii the x values are negative and the y values are also positive using this fact find the point that has x negative and y positive.
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Answer:
h³- 8h² + 16h
Step-by-step explanation:
The problem tells us that the length and width of these boxes are both 4 inches less than the height of the box.
So if we name <u>h the height of the box</u>, the <u>width of the box would be h - 4 </u>and the <u>height of the box would be h - 4.</u>
Now, the volume of a rectangular prism is given by V = height x width x length
So, considering the values we have in this problem we get:
V= height x width x volume
V = h (h-4)(h-4)
V= h(h-4)²
V= h (h²-8h + 16)
V = h³- 8h² + 16h
Therefore, the polynomial representing the volume of this box in terms of the height is h³- 8h² + 16h
Multiply 1/3 by any number higher than 2 and you can have equivalent fractions.
Ex:
1/3×3/3=3/9
