In a game you flip a coin twice, and record the number of heads that occur. You get 10 points for 2 heads, zero points for 1 hea d, and 5 points for no heads. What is the expected value for the number of points you’ll win per turn?
1 answer:
Answer:
Step-by-step explanation:
P(2 heads) = P(first flip = head)*P(second flip = head)
=> =
P(1 head) = P(first flip = head)*P(second flip = tail) + P(first flip = tail)*P(second flip = head)
=
P(no heads) = P(first flip = tail)*P(second flip = tail)
=
E(winning) =
=
=
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