The figure below shows a circular lawn. Its diameter is 26ft. 26ft (a) Use the calculator to find the area and circumference of
the lawn. Use 3.14 for π in your calculations, and do not round your answers. Make sure to include the correct units. Area: Circumference: (b) Fertilizer will be applied to the lawn. Which measure would be used in finding the amount of fertilizer needed? Circumference Area (c) The lawn will be surrounded by tape. Which measure would be used in finding the amount of tape needed? Circumference Area
1 answer:
The area and the circumference of the circle are 530.93 square ft and 81.68 ft. If fertilizer will be applied to the lawn. Then the area is used. If the lawn will be surrounded by tape. Then the circumference is used.
<h3>What is a circle?</h3>It is the centre of an equidistant point drawn from the centre. The radius of a circle is the distance between the centre and the circumference.
The figure below shows a circular lawn. Its diameter is 26 ft.
Then the area of the circle will be
Then the circumference of the circle will be
Circumference = π d
Circumference = π × 26
Circumference = 81.68 ft
If fertilizer will be applied to the lawn. Then the area is used.
If the lawn will be surrounded by tape. Then the circumference is used.
More about the circle link is given below.
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Answer:
There will be no change in C and D but E must increase.
Step-by-step explanation:
We are given a equation of circle as:
it could also be represented in general form of equation of circle as:
( since we add both the side of the equality by and
)
Hence, on comparing the equation with general form of the equation:
The center of circle is (g,h) and radius is r.
Here we have the center as:
and radius is given aS:
As there is no change in the center hence the value of and
remains unchanged i.e. the value of C and D remains unchanged.
Now we are given that the radius of the circle is decreased.
that means the change in radius is due to the change in E.
Hence for the quantity to decrease E must increase so that the total quantity decreases.
Hence there will be no change in C and D but E must increase in order to decrease the radius of circle.