Answer:
f(x + 3) = (4x + 13)/(x - 3)
Step-by-step explanation:
If f(x) = (4x + 1)/(x - 6)
then in f(x + 3)...js replace x with (x + 3)...
f(x + 3) = (4(x + 3) + 1)/(x + 3 - 6)
;f(x + 3) = (4x + 13)/(x - 3)
Since f(x) is (strictly) increasing, we know that it is one-to-one and has an inverse f^(-1)(x). Then we can apply the inverse function theorem. Suppose f(a) = b and a = f^(-1)(b). By definition of inverse function, we have
f^(-1)(f(x)) = x
Differentiating with the chain rule gives
(f^(-1))'(f(x)) f'(x) = 1
so that
(f^(-1))'(f(x)) = 1/f'(x)
Let x = a; then
(f^(-1))'(f(a)) = 1/f'(a)
(f^(-1))'(b) = 1/f'(a)
In particular, we take a = 2 and b = 7; then
(f^(-1))'(7) = 1/f'(2) = 1/5
The answer is A. Working the formula backwards you get that r^2=256, so r=16
Answer:
Asriel is correct because 2 times 2 is 4 and 2 times 3 is 6 and 2 times 5 is 10 so Asriel is correct.
Answer:
0.04 or 4%
Step-by-step explanation:
point estimate of proportion:
(0.6+0.68)/2
1.28/2
0.64
Margin of error:
0.68 - 0.64 = 0.04
0.04×100 = 4%
