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seropon [69]
3 years ago
5

BRUH I NEED HELP PLEASE !!! Enter your answer as a whole number or a fraction in simplest form

Mathematics
2 answers:
saul85 [17]3 years ago
7 0
The slope would be 1/4

if you count up one and over four from the first point, you’ll get to the second point, and slope equals rise over run
iren2701 [21]3 years ago
5 0

Answer:

what was the zoom thing again???

Step-by-step explanation:

You might be interested in
The equation of a plane in space is x + 3y + 2z = 6.. a.)Accurately sketch the plane on the set of axes, showing all your calcul
nlexa [21]
In getting the value of X, Y and Z in the equations X+3Y+2Z = 6 you must first substitute the variables into 0 and came up with the value of X=6, Y=2, and Z =3. So the volume of this pyramid is computed using V=1/3AH and the volume is 9. i hope you are satisfied with my answer 
4 0
3 years ago
PLEASE! PLEASE! help!
qaws [65]
1.) The answer is 825.75 (multiply the given tax rates to the gross pay)
    2,785 x 13% federal taxes = 362.05
    2,785 x 9% state tax         = 250.65
    2,785 x 7.65% FICA          = <u>213.05
</u>                                                 825.75
<u>
</u>2.) The answer is 288.60 (multiply the interest rate to the balance, no need to add a late payment fee since they paid on 6/1, not after)
    2,748.56 x 10.5% = 288.60

3.) The answer is 182.13  (multiply the APR to the original purchase price, no need to add the sales tax)
<u />    1,500 x 11.75% = 182.13

4.) The answer is 371.92 (deduct the reward to the interest)
    Interest : 2,975.34 x 13.5% = 401.67
    Reward : 2,975.34 x 1%      = <u>  29.75</u>  
                                                    371.92

5.) The answer is  1,339.13 (deduct the interest to the monthly payment)
    Monthly payment : 2,236.00
    Monthly interest :   <u>   896.87</u> [(231,450 x 4.65%) / 12 months]
<u />                                    1,339.13

Hope this helps! :)
4 0
3 years ago
A store manager paid $95 for an item and set the selling price at $116.85. What was the percent markup?
Neporo4naja [7]

We have been given that a store manager paid $95 for an item and set the selling price at $116.85. We are asked to find the percent mark-up.

We will use percent increase formula to solve our given problem.  

\text{Percent increase}=\frac{\text{Final}-\text{Initial}}{\text{Initial}}\times 100\%

\text{Percent increase}=\frac{\$116.85-\$95}{\$95}\times 100\%

\text{Percent increase}=\frac{\$21.85}{\$95}\times 100\%

\text{Percent increase}=0.23\times 100\%

\text{Percent increase}=23\%

Therefore, the mark-up will be 23% and option 'b' is the correct choice.

6 0
3 years ago
Need answer thanks! only answer if you know please​!
Vaselesa [24]

Answer:

a) k \approx 0.0602\,\frac{1}{min} (k\approx  6.02\,\frac{\%}{min}), b) k \approx 0.0648\,\frac{1}{min} (k \approx 6.48\,\frac{\%}{min}), c) t_{1/2} \approx 60.274\,days, d) t_{1/2}\approx 4.305\,min, e) k \approx 0.3\,\frac{1}{min} (k\approx 30\,\frac{\%}{min}), f) k \approx 0.0120\,\frac{1}{min} (k \approx 1.20\,\frac{\%}{min}), g) k \approx 2.876\times 10^{-5}\,\frac{1}{yr} (k \approx 2.876\times 10^{-3}\,\frac{\%}{yr})

Step-by-step explanation:

All radioactive isotopes decay exponentially, the mass of the isotope as a function of time (m(t)), measured in grams, is defined by:

m(t) = m_{o}\cdot e^{-k\cdot t} (1)

Where:

m_{o} - Initial mass of the isotope, measured in grams.

k - Decay rate, measured in \frac{1}{min} or \frac{1}{day} or \frac{1}{yr}.

t - Time, measured in minutes, days or years.

We define the decay rate in terms of half-life by using the following expression:

k = \frac{\ln 2}{t_{1/2}} (2)

Where t_{1/2} is the half-life of the isotope, measured in minutes or years.

Now we proceed to determine the missing values:

a) Polonium-200 (t_{1/2} = 11.5\,min)

k = \frac{\ln 2}{11.5\,min}

k \approx 0.0602\,\frac{1}{min}

b) Lead-194 (t_{1/2} = 10.7\,min)

k = \frac{\ln 2}{10.7\,min}

k \approx 0.0648\,\frac{1}{min}

c) Iodine-125 (k = 0.0115\,\frac{1}{day})

t_{1/2} = \frac{\ln 2}{k}

t_{1/2} = \frac{\ln 2}{0.0115\,\frac{1}{day} }

t_{1/2} \approx 60.274\,days

d) Kryption-75 (k = 0.161\,\frac{1}{min})

t_{1/2} = \frac{\ln 2}{k}

t_{1/2} = \frac{\ln 2}{0.161\,\frac{1}{min} }

t_{1/2}\approx 4.305\,min

e) Strontium-79 (t_{1/2} = 2.3\,min)

k = \frac{\ln 2}{2.3\,min}

k \approx 0.3\,\frac{1}{min}

f) Uranium-229 (t_{1/2} = 58\,min)

k = \frac{\ln 2}{58\,min}

k \approx 0.0120\,\frac{1}{min}

g) Plutonium-239 (t_{1/2} = 24100\,yr)

k = \frac{\ln 2}{24100\,yr}

k \approx 2.876\times 10^{-5}\,\frac{1}{yr}

6 0
3 years ago
Which of the following are the factors of t4 – 81?
nata0808 [166]
t^4 - 81 =\\\\(t^2)^2 - (9)^2=\\\\(t^2 - 9)(t^2 + 9) =\\\\\boxed{\bf{ (t-3)(t+3)(t^2 + 9)}}

Your answer is B.
7 0
4 years ago
Read 2 more answers
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