<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
7 9/11 = 7.81 with a line over the 81 because it is repeating
15/720 = 0.020
7.58
7.812
least to greatest : 15/720, 7.58 , 7.812 , 7 9/11
Answer:
x+3, y-4
Step-by-step explanation:
You are moving the triangle 3 to the right, so x+3, an 4 down, so y-4.
Answer:
x = 1/26
Step-by-step explanation:
(26)x = 1
26x = 1
x = 1/26
