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grin007 [14]
3 years ago
5

Anybody know the answer to these

Mathematics
2 answers:
il63 [147K]3 years ago
8 0
1 and a for part 1 and part b
Anettt [7]3 years ago
3 0
I think it’s 1 a and 1 b
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Solve the following system of equations algebraically:<br> 4x - 5y = 18<br> 3x – 2y = 10
fiasKO [112]

Answer:

D

Step-by-step explanation:

Given the 2 equations

4x - 5y = 18 → (1)

3x - 2y = 10 → (2)

Multiplying (1) by 3 and (2) by - 4, then adding will eliminate the x- term

12x - 15y = 54 → (3)

- 12x + 8y = - 40 → (4)

Add (3) and (4) term by term to eliminate x, that is

- 7y = 14 ( divide both sides by - 7 )

y = - 2

Substitute y = - 2 into either of the 2 equations and solve for x

Substituting into (1)

4x - 5(- 2) = 18

4x + 10 = 18 ( subtract 10 from both sides )

4x = 8 ( divide both sides by 4 )

x = 2

solution is (2, - 2 ) → D

8 0
3 years ago
Helpppp pleaseeee thannkkss
bekas [8.4K]
Choice A is the answer

Why? Because we start with 4, which is denoted a_1 = 4, and because we multiply each previous term by -3 to get the next term (which is what the second row of choice A says). 
6 0
3 years ago
solve |1 - 4x| &gt; 7 a. {x|x &lt; -1.5 ∪ x &gt; 1.5} b. {x|x &lt; -1.5 ∪ x &gt; 2} c. {x|-1.5 &lt; x &lt; 2}
skelet666 [1.2K]
<span>|1 - 4x| > 7
</span>(<span>1 - 4x) > 7 or (</span><span>1 - 4x) < -7
-4x > 7 - 1 or -4x < -7 - 1
-4x > 6 or -4x < -8
x < 6/-4 or x > -8/-4
x < -1.5 or x > 2
</span><span>{x|x < -1.5 ∪ x > 2}</span>
8 0
3 years ago
Which equation is a point-slope form of the equation of this line (-2, 1 ) and (1, 7 )
lana [24]

The point-slope formula:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have (-2, 1) and (1, 7).

Substitute:

m=\dfrac{7-1}{1-(-2)}=\dfrac{6}{3}=2

y-1=2(x-(-2))\\\\y-1=2(x+2)

6 0
2 years ago
ASAP plz answers just
faust18 [17]

Answer:

<em>(a) x(x+2)  (b) 2x(x-3)  (c) 5x(3-2x^2)  (d) 3x^2(3+x)</em>

Step-by-step explanation:

For each expression, <u>we need to factor out the GCF(Greatest common factor)</u>

a)   x^2+2x

Here, the GCF is  x. So, we will get.....

x^2+2x\\ \\ =x(\frac{x^2}{x}+ \frac{2x}{x}) \\ \\ =x(x+2)

b)   2x^2-6x

Here, the GCF is  2x. So, we will get......

2x^2-6x\\ \\ =2x(\frac{2x^2}{2x}- \frac{6x}{2x}) \\ \\ =2x(x-3)

c)   15x-10x^3

Here, the GCF is  5x. So, we will get.......

15x-10x^3\\ \\ =5x(\frac{15x}{5x}- \frac{10x^3}{5x}) \\ \\ =5x(3-2x^2)

d)   9x^2+3x^3

Here, the GCF is  3x^2. So, we will get.......

9x^2+3x^3\\ \\ =3x^2(\frac{9x^2}{3x^2}+ \frac{3x^3}{3x^2}) \\ \\ =3x^2(3+x)

8 0
3 years ago
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