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melomori [17]
3 years ago
5

Consider the accompanying matrix as the augmented matrix of a linear system. State in words the next two elementary row operatio

ns that should be performed in the process of solving the system
[1 -5 3 0 -2

0 3 -7 0 4

0 0 1 2 -2]
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The next step to solve the system, would be to divide the second row by 3 and we would be left with:  3 * R2

[1 -5 3 0 -2

0 1 -7/3 0 4/3

0 0 1 2 -2]

Then what we will do is multiply row 3 by 7/3 and then subtract it from row 2, that is, R2 - 7/3 * R3, and it would look like this:

[1 -5 3 0 -2

0 1 0 14/3 -10/3

0 0 1 2 -2]

And these would be the next two steps in the process of solving the system.

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what is the equation to seven less than the product of twice a number is greater than 5 more than the same number
postnew [5]
<span>seven less than (-7) than the product of twice a number (2x) is greater than (>) five more than (+5) the same number (x)

2x-7>x+5
treat the > sign as an equals for now
2x-7=x+5
subtract x from both sides
x-7=5
add 7 to both sides
x=12
put the > sign back in
x>12</span>
7 0
4 years ago
Read 2 more answers
What is the answer
Nastasia [14]

Answer:

both

Step-by-step explanation:

neither of those can be an answer. because x is less than or equal to -1

5 0
3 years ago
Bob is on the school swim team and has practice 4 days per week. He has to practice twice per day, in the morning and in the eve
mylen [45]

Answer:

1h every morning

Step-by-step explanation:

3 0
3 years ago
A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri
nlexa [21]

Answer:

df=categor-1=6-1=5

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got \chi^2_{critc}= 11.0705

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday  Tuesday  Wednesday Thursday Friday Saturday    Total

 12             9                 11                 10           9            9              60

The level of significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{60}{6}= 10 and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

df=categor-1=6-1=5

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got \chi^2_{critc}= 11.0705

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0
3 years ago
1 7/8 divided by 3/4 can someone please help me
sesenic [268]
1. Change 1 7/8 to an improper fraction, which gives you 15/8.

2. Use KFC to divide fractions. KEEP the first term, FLIP the second and CHANGE to multiplication.

3. 15/8 x 4/3 = 60/24 = 2 1/2
3 0
3 years ago
Read 2 more answers
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