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3 years ago

C' (-3,5)

Mathematics

2 answers:

kherson [118]3 years ago

5 0

Answer:

D. a reflection over the y-axis

arsen [322]3 years ago

3 0

Answer:

C. a reflection over the y-axis

Step-by-step explanation:

Notice how the x-values change from negative to positive while the y values stay the same. This will mean that original is being reflected over an axis. Since only the x-values are changing that would mean that it is being reflected over the y-axis.

Hope this helps :)

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ASAP IF U DO THIS IMMA MARK YOU BRANLIEST

steposvetlana [31]

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3 years ago

What Is a area with dimensions 1 unit times 1 unit

Ludmilka [50]

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2 years ago

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

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1 year ago

A cafe has 6 indoor tables and 2 outdoor tables. Each indoor table has 8 chairs, and each outdoor table has 5 chairs. How many c

Makovka662 [10]

Indoor
8 chairs x 6 (for each table) =48 indoor chairs
Outdoor
5 chairs x 2 (for each table) =10 outdoor chairs
Final Answer
48 indoor chairs+10 outdoor chairs=58 chairs
58 chairs in total

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2 years ago

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mars1129 [50]

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Step-by-step explanation:

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2 years ago