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3 years ago

PLEASEEEE HURRY

Mathematics

1 answer:

nika2105 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

The y values increase by 2 every time so 18+2=22

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What is the greatest common factor of 12 and 18? A. 2 B. 6 C. 4 D. 12

S_A_V [24]

Answer:

B. 6

Step-by-step explanation:

D. 12 cant be multiplied to get 18

C. 4 cant be multiplied to get 18

A. 2 is a common factor of 12 and 18 but not the greatest.

B. 6 times 2 is 12 and 6 times 3 is 18 so 6 is the greatest common factor.

4 0

2 years ago

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A right triangle has a base of 11 yards and a height of 7 yards . If you were to construct a similar but not congruent right tri

Dimas [21]

Answer:

bae of 44 yds and a height of 28 yds

Step-by-step explanation:

11x7 = 88 yd^2 = area of small triangle

616/88 = 16 so the larger triangle area is 16 times larger than the smaller triangle.

The area of a triangle is not proportional to it's dimensions. An increase of 16 times the area only increases the dimensions by 4 times.

larger triangle dimensions are 11 x 4 = 44 and 7 x 4 = 28

5 0

3 years ago

What is 9/12 in simplest form

olga nikolaevna [1]

Solutions

⇒9/12

1) To see if 9/12 is in simplest form you have to find 9 and 12's GCF.
The GCF of 9 and 12 is 3

2) Divide by the GCF
9 ÷ 3 = 3
12 ÷ 3= 4

3/4 is answer

6 0

3 years ago

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Will mark brainliest

Anastasy [175]

Answer:

Step-by-step explanation:

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3 years ago

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Given that y is directly proportional to x^2 and that y=2 when x=3 find the value of y when x=6

Sergio039 [100]

Answer:y=4/3

y is directly proportional to x^2 is written as

$y \alpha {x}^{2}$ introducing a constant,

y=kx^2

but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

$2 = {3}^{2} \times k$

2=9k . dividing through by 9 to get the value of k

 $\frac{2}{9} = \frac{9k}{9}$ 

 $k = \frac{2}{9}$ 

putting it in the general expression

 $y = \frac{2}{9} x$ 

the value of y when x=6

 $y = \frac{2}{9} \times 6$ 

 $y = \frac{4}{3}$ 

therefore the value of y when x=6 is

4/3

3 0

3 years ago