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seraphim [82]
3 years ago
13

Exponential form of root 3^2y

Mathematics
1 answer:
bonufazy [111]3 years ago
7 0

Answer:

Please remember

n

√

x

is written as

x

1

n

in exponential form

Hence

3

√

x

2

y

can written as

(

x

2

y

)

1

3

As

(

x

a

)

b

is nothing but

x

a

⋅

b

3

√

x

2

y

=

(

x

2

y

)

1

3

=

x

2

⋅

(

1

3

)

*

y

1

3

=

x

2

3

*

y

1

3

Step-by-step explanation:

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Plz help i need to rase my grade
jeka57 [31]

The average of anything is calculated by adding up all the terms in the data set and dividing by the amount of terms in the data set.

In this problem,

The average = $1000

the amount of terms = 3

x = the amount earned Sunday

($1073 + $1108 + x) / 3 = $1000

First, multiply both sides by 3

$1073 + $1108 + x = $3000

Add together like terms

$2181 + x = $3000

Subtract $2181 from both sides.

x = $819

The restaurant needs to earn $819 on Sunday to have an average of $1000

6 0
3 years ago
Solve: 8+ x/2= 1/4 (x-4)-1
alexandr402 [8]
|3x+1|=4 : x=−
5
3 ​or x=1
Pasos
|3x+1|=4
Aplicar las propiedades de los valores absolutos: Pi |u| = a, a>0 entonces u = a or u = −a
3x+1=−4 or 3x+1=4
Mostrar pasos
3x+1=−4 or 3x+1=4
6 0
3 years ago
Larry deposits $15,000.00 into his savings account that earns 9% interest compounded annually. How much money is in the account
garri49 [273]

Answer:

Answer: 31,200

Step-by-step explanation:

Every year, 9% interest, or $1,350, is being added to the account. $1,350x12=16,200

16,200 + 15,000 = 31,200

3 0
3 years ago
7. Make a box-and-whisker plot for the data. What is the upper quartile value?
Nookie1986 [14]

In order to draw the Box-whisker plot, we need to rewrite the data in increasing order.

42 43 47 48 51 52 56 56 58 60 62 64 65 66

Mean of the data = (42 + 43 + 47 + 48 + 51 + 52 + 56 + 56 + 58 + 60 + 62 + 64

+ 65 + 66) ÷ 14

Mean of the data = 770 ÷ 14

Mean of the data = 55

Median = (56 + 56) ÷ 2

Median = 112 ÷ 2

Median = 56

Lowest value = 42

Highest value = 66

Range = Highest value - Highest value

Range = 66 - 42

Range = 24

Lower Quartile = 25% of the data

Lower Quartile = 48

Upper Quartile = 75% of the data

Upper Quartile = 62

6 0
3 years ago
The vertices of the feasible region are (choose all that apply)
Anarel [89]

9514 1404 393

Answer:

  (0,0)

  (0,3)

  (3,2)

  (4,0)

Step-by-step explanation:

The feasible region is the doubly-shaded area in the lower left corner of the first quadrant. It is a quadrilateral, so has 4 vertices. Those are the vertices of the feasible region:

  (0,0)

  (0,3)

  (3,2)

  (4,0)

_____

<em>Additional comment</em>

The objective function has positive slope, so the point (4, 0) will maximize it, and the point (0, 3) will minimize it.

5 0
3 years ago
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