BC is perpendicular to AC

Mathematics

1 answer:

FromTheMoon [43]3 years ago

5 0

Answer:

In ∆ABC, AD is perpendicular while BC and BE are perpendicular to AC.

Step-by-step explanation:

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A right angle has an area of 13m*2. The dimensions of the triangle are increased by a scale factor of 3. What is the area of the

Alex_Xolod [135]

The answer is: 117m²

The explanation is shown below:

1. You have the following information given in the problem:

- The triangle has an area of 13 m².

- The dimensions of the triangle are increased by a scale factor of 3.

2. Therefore, to solve the exercise you must multiply the area by $3^{2}=9$ , as following:

$A=(13m^{2})(9)\\A=117m^{2}$

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3 years ago

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Read 2 more answers

Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa

xenn [34]

$Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$Steps:$

$\left|3x+8\right|-9=-5$

$\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9$

$\mathrm{Simplify},\\\left|3x+8\right|=4$

$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4$

$3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4$

$3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}$