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3 years ago

I need help with this question

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

Answer:

y = -3x + 8

Step-by-step explanation:

You have to find the slope first using the formula $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$

Insert any two points in the equation (1,5) and (2,2) and you get -3.

Then, you do any x value times the slope (1*-3 = -3) and add so that it equals the corresponding y value (8).

This makes it y = -3x + 8.

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Answer:

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Step-by-step explanation:

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A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y

siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32

Given that 100 beetles are released into a field.

So that means initial number of beetles P=100

Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

$A=P(1+r)^n$ where A is number of beetles at any year n.

Plug the given values into above formula we get:

$A=100(1+0.32)^n$

$A=100(1.32)^n$

now plug n=10 years

$A=100(1.32)^{10}=100(16.0597696605)=1605.97696605$

Hence answer is approx 1606 beetles will be there after 20 years.

Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

$A=100(1.32)^{20}=100(257.916201549)=25791.6201549$

Hence answer is approx 25791 beetles will be there after 20 years.

Now we have to find time for 100000 beetles so plug A=100000

$A=100(1.32)^n$

$100000=100(1.32)^n$

$1000=(1.32)^n$

$log(1000)=n*log(1.32)$

$\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n$

33.174666862=n

Hence answer is approx 33 years.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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