Let the number of bike be x and the number of skates be y, then
21x + 20y ≥ 362 . . . (1)
2y = x . . . (2)
Putting (2) into (1), then
21(2y) + 20y ≥ 362
42y + 20y ≥ 362
62y ≥ 362
y ≥ 5.84
The least number of pairs of skates they need to rent each day to make their minimum is 6.
        
             
        
        
        
Answer:
A. x=0
Step-by-step explanation:
x+20+10x=20+9x
cancel equal terms
x+10x+9x
add x to 10x
11x=9x
move variable to left
11x-9x=0
subtract 11x to 9x
2x=0
divide Both sides by 2
x=0
 
        
             
        
        
        
Answer:  
Step-by-step explanation:
Given : A man earned x pesos in 10 days and spent y pesos during each of those days. 
i.e. Total earning in 10 days = x
Earning per day = [By unitary method]    (1)
    [By unitary method]    (1)
Money spent per day =y      (2)
We know that

i.e. Subtract (2) from (1), we get

Hence, the expression to determine how many pesos he saved per day will be:-

 
        
             
        
        
        
Trick question. For the reflections given in the problem statement, the x-coordinate doesn't change. The number that goes in the green box is 1.