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3 years ago

How many solutions does the equation - 8x + 5 = - 8x + 4 have

Mathematics

1 answer:

KiRa [710]3 years ago

3 0

$- 8x + 5 = - 8x + 4 \\ - 8x = - 8x + 4 - 5 \\ - 8x = - 8x - 1 \\ 0 = - 1(false)$

we don't have solutions !!

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Please someone help!

pochemuha

Your answer is 19 5/4

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3 years ago

Read 2 more answers

Micheal has 4 red shirts, 3 green shirts, and 5 blue shirts in his closet. If he randomly selects a shirt, what is the probabili

LenKa [72]

Answer:

D. 7/12

Step-by-step explanation:

First, find the total number of shirts in his closet:

4 + 3 + 5

= 12

Now, find how many are green or red:

4 + 3

= 7

Since 7 out of 12 shirts are green or red, the probability that Micheal chooses green or red is D. 7/12

8 0

3 years ago

Note the graph of an athletes performance after finishing a triathlon. The x-axis measures time in hours, and the y axis measure

olasank [31]

The only incorrect statement is C)
The athlete was biking between [1,3] and running between [3,6]. The durations of 2 and 3 are not equal.

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3 years ago

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never [62]

It would be 12.5 square miles I would appreciate the Brainliest

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3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago