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Anarel [89]
2 years ago
6

4.An equilateral triangle has sides of length ad? V3Show that the area is4​

Mathematics
1 answer:
Reika [66]2 years ago
5 0

Answer:

\frac{ \sqrt{3} }{2} a {}^{2}

Step-by-step explanation:

the side of equilateral triangle = a

so, area =

\frac{ \sqrt{ 3} }{2}  \times side {}^{2}

=》

\frac{ \sqrt{3} }{2}   \times a {}^{2}

=》

\frac{ \sqrt{3} }{2} a {}^{2}

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Solve the equation then check your solution 5p=140 <br> A)28<br> B)700<br> C)-28<br> D)26
Kruka [31]

Answer:

p=28

Step-by-step explanation:

5p=140

To to find the value of p divide both sides by 5 (5p/5 and 140/5)

p=28!


4 0
3 years ago
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Given sin thata = 2/5 and 0° &lt; thata &lt; 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
3 years ago
Which point on the number line below best represent 30
san4es73 [151]
Where’s the number line?
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What is the coefficient of y int the expression 2x4+3y
lapo4ka [179]
The coefficient of y = 3

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6 0
3 years ago
An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
Rzqust [24]

Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0
2 years ago
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