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il63 [147K]
3 years ago
7

Find the radical equivalent of 27^2/3 and compute it. please help i'm taking a test.

Mathematics
2 answers:
AveGali [126]3 years ago
6 0
Note that (a^b)^c=a^(bc) so in this case we have:

(27^(1/3))^2  the cube root of 27=±3

(±3)^2  and ±3^2=9

So the equivalent expression is 9  or if you need an exponent 9^1 :)

I am assuming that you meant 27^(2/3)
irina1246 [14]3 years ago
3 0

Answer:

Step-by-step explanation:

27^(2/3) = [cube root (27)]^2 = 3^2 = 9

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If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
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First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

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Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

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As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

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