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krek1111 [17]
3 years ago
6

A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i

s driving towards him at 65 mph? Note vsound = fλ, where vsound (the speed of sound in air) is 345 m/s. Also, 1 mile = 1.609 km.
Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

we can use formula

f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

f_s=2000Hz

v_a=345m/s

v_p=65mph

now, we can change it into m/s

v_p=65*\frac{1609}{3600}m/s

v_p=29.05139m/s

now, we can plug it

f_L=2000(\frac{345-29.05139}{345+29.05139} )

f_L=1689.33263Hz..............Answer

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<img src="https://tex.z-dn.net/?f=32.5%20%3D%2030%20%2B%20%20%5Cfrac%7B20%20-%20%2840%20%2B%20x%29%7D%7B12%7D%20%20%5Ctimes%2010
erastova [34]

Answer:

x =  - 23

Step-by-step explanation:

\frac{20 - (40 + x)}{12}  \times 10 = 32.5 - 30 = 2.5

=  >  \frac{20 - (40 + x)}{12}  = 0.25

=  >  \frac{20 - (40 + x)}{12}  =  \frac{1}{4}

=  > 20 - (40 + x) =  \frac{12}{4}  = 3

=  > 40 + x = 20 - 3 = 17

=  > x = 17 - 40 =  - 23

7 0
3 years ago
If 4x-3y=2, what is the value of 16^x/8^y
gogolik [260]

16 is the correct answer

7 0
3 years ago
PLS HELP!! GIVING BRAINLIEST TO FIRST CORRECT ANSWER!!+50 POINTS
Elena-2011 [213]

Answer(s):

  • 154 in²
  • 3168/7 km²
  • 38.5 m²

Revising the area of a circle formula

We already know that the area of a circle is expressed as \pi r^{2}.

  • The "r" variable is known as the radius.
<h2><u>Solving each problem given:</u></h2><h3>Solving Problem 4:</h3>

We are given the radius of circle, which is 7 in. Let us substitute the radius in the formula. Once substituted, we can simplify the expression obtained to determine the area of the circle shown in the picture.

\implies \pi (7)^{2}

<u>Take π as 22/7</u>

\implies \huge\text{(}\dfrac{22}{7} \huge\text{)}(7)^{2}<em> </em>

\implies \huge\text{(}\dfrac{22}{7} \huge\text{)}(7)(7)

\implies (22)(7)

\implies 154 \ \text{in}^{2}

<h3>Solving Problem 5:</h3>

In this problem, we are given the diameter to be 24 kilometers. Since the radius of the circle is half the diameter, we can tell that the radius of the circle is 24/2 kilometers, which is 12 kilometers.

\implies \pi (12)^{2}

<u>Take π as 22/7</u>

\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (12)^{2}

\implies \huge\text{(}\dfrac{22}{7}\huge\text{)} (12)(12)

\implies \dfrac{3168}{7} \ \text{km}^{2}

<h3>Solving Problem 6:</h3>

We are given the radius of circle, which is 3.5 in. Let us substitute the radius in the formula. Once substituted, we can simplify the expression obtained to determine the area of the circle shown in the picture.

\implies \pi (3.5)^{2}

<u>Take π as 22/7</u>

\implies \huge\text{(}\dfrac{22}{7}\huge\text{)}  (3.5)^{2}

\implies \huge\text{(}\dfrac{22}{7}\huge\text{)}  (3.5)(3.5)

\implies \huge\text{(}\dfrac{22}{2}\huge\text{)} (3.5) = (11) (3.5)

\implies 38.5 \ \text{m}^{2}

Note: <em>The radius given in this problem was not clearly stated. If the radius I stated here, is incorrect, please notify me in the comments. Thanks!</em>

Learn more about area of circles: brainly.com/question/12414551

3 0
2 years ago
3. A car starts a trip with 20 gallons of gas in its tank. The car traveled at an average
Helga [31]

Answer:

32.5%

Step-by-step explanation:

first we will have to calculate how much miles the car traveled, to do that we will multiply the speed by hour long the car was traveling for which is

65*3=195

During those 195 miles the car used 1 gallon for every 30 miles which means it used 6.5 gallons of its tank

195/30=6.5

6.5 gallons is 32.5% of 20 gallons

6.5/20=0.325

0.325 * 100 = 32.5%

3 0
3 years ago
A rock is projected directly upward from ground level with an initial velocity of 90 ft/sec. After how many seconds will it retu
Nastasia [14]
For this case we have the following equation of motion:
 h (t) = -16t ^ 2 + 90t
 Equaling the equation to zero we have:
 -16t ^ 2 + 90t = 0
 We look for the roots of the polynomial:
 (t) (- 16t + 90) = 0
 t1 = 0 (initial position)
 t2 = 90/16 = 5.625 s (time it reaches the ground again)
 Answer:
 
it will return to the ground in:
 
t = 5.625 s
4 0
4 years ago
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