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Cerrena [4.2K]
2 years ago
5

Solve for W 4w^2+9w= -2

Mathematics
1 answer:
7nadin3 [17]2 years ago
3 0

Answer:

w_1=-\frac{1}{4},w_2=-2}

Step-by-step explanation:

4w^2+9w=-2

4w^2+9w+2=0

w^2+9w+8=0

(w+1)(w+8)=0

(4w+1)(w+2)=0

w_1=-\frac{1}{4},w_2=-2}

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Alika [10]

60/8 = 7.4. The dog is faster.  35/5 = 7

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3 years ago
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kiruha [24]

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6 0
3 years ago
Help!!!i never learned this
andre [41]
I hope this helps you



perpendicular lines slopes multiplication -1


M1×M2= -1


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5 0
3 years ago
In​ Marissa's calculus​ course, attendance counts for 15​% of the​ grade, quizzes count for 20​% of the​ grade, exams count for
Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

Attendance counts for 15% of the grade and she has 100% average on that. So we have:

attendance = weight*(Marissa's average)

attendance = 15%*(100/100) = 15%

Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

Quizzes = 20%*(93/100) = 18.6 %

Exams counts for 50% of the grade and she has a 82% average on that. So we have:

Exams = weigth*(Marissa's average)

Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

Finals = 15%*(85/100) = 12.75%

So her grade is the sum of all the cattegories:

Course's average = 15+18.6+41+12.75 = 87.35 %

4 0
3 years ago
Read 2 more answers
3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!
Nezavi [6.7K]
\text{Volume}=129.87cm^3

Explanation

Step 1

the density of an object is given by:

\text{density}=\text{ }\frac{mass}{\text{volume}}

Step 2

let

\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\  \end{gathered}

Step 3

replace,

\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\  \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}

I hope this helps you

5 0
1 year ago
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