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Marizza181 [45]
3 years ago
5

James Ran 1/4 of a mile in the morning and then ran 2/8 of a mile that evening what was the distance James ran

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

1/2

Step-by-step explanation:

1/4=2/8

2/8+2/8=4/8=1/2

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two paintings both have a current value of $15,000. The estimated value of each painting over the next five years is shown in th
gulaghasi [49]

Answer:

B.

Step-by-step explanation:

painting a increases expoonentially

1.05(A value)= N

same for painting b by 1.02x

but a increases .3 %more

6 0
3 years ago
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In a small chess tournament, 20 matches were played. Find out how many people were involved if it is known that each participant
Nina [5.8K]

Answer:

<em>5</em><em> players participated in the tournament.</em>

Step-by-step explanation:

In a small chess tournament, 20 matches were played.

Let us assume that n number of players participated in the tournament

As in each game 2 players play, so the number of ways they can play is,

=\ ^nC_2

As they played 2 games with every other participant in the tournament.

So the total number of games is,

=\ 2\times ^nC_2

But it is given to be 20, so

\Rightarrow \ 2\times ^nC_2=20

\Rightarrow \ ^nC_2=10

\Rightarrow \dfrac{n!}{2!(n-2)!}=10

\Rightarrow \dfrac{n(n-1)}{2}=10

\Rightarrow {n(n-1)=20

As 5\times 4=20, so we get n=5.

Therefore, 5 players participated in the tournament.

5 0
3 years ago
Read 2 more answers
17 m<br> 15 m<br> 17 m<br> 11 m<br> 16 m<br> PLEASE HELP ME I WILL THANK YOU LATERR :)))
REY [17]

Answer:

790  for surface area

1800 for volume

Step-by-step explanation:

3 0
3 years ago
What s the domain of f(x)=3x-2
Dmitry_Shevchenko [17]
Domain of: 3x-2

Solution: -Inf < x < Inf

Interval Notation: (-Inf, Inf)

Inf = Infinity (Replace "Inf" with the infinity symbol)

"-" = Negative sign
5 0
3 years ago
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The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
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