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3 years ago

How do you write 2.3 x 103 in standard form?

Mathematics

1 answer:

Misha Larkins [42]3 years ago

7 0

Answer:

2300

Step-by-step explanation:

$2.3 \times {10}^{3} \\ \\ = 2.3 \times 1000 \\ \\ = 2300$

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Which lists all of the y-intercepts of the continuous

8090 [49]

Answer: (0,0)

Step-by-step explanation:

got it correct

5 0

3 years ago

Can someone explain interval notations? Also, How do you figure them out?

sergeinik [125]

A notation for representing an interval as a pair of numbers. The numbers are the endpoints of the interval. Parentheses and/or brackets are used to show whether the endpoints are excluded or included.

For example, [3, 8) is the interval of real numbers between 3 and 8, including 3 and excluding 8.

8 0

3 years ago

I need the answer please and can u answer my recent to.

ale4655 [162]

Answer:

30 hours.

Step-by-step explanation:

Richard can build 15 snowballs in 1 hour

But 2 snowballs melt every 15 minutes

In 1 hour, the number of snowballs that will have melted is:

$\frac{60}{15}$ × 2 = 8

The number of snowballs that will have remained = 15 - 8 = 7

So 7 snowballs will have remained in 1 hour

For 210 snowballs to have remained, it will take:

$\frac{210}{7}$ × 1 = 30 hours.

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3 years ago

Brainlist and 45 Points

shtirl [24]

Answer:

Step-by-step explanation:

The only option with coordinates within the triangle is D.

Coordinates included within the triangle. (-1, 0), (-1, -2), and (-1, -1)

(-1, -1) is the only one listed in the given options.

5 0

3 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

3 years ago