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Over [174]
3 years ago
13

It rained 9 days in March. What percent of the month did it rain? (There are 31 days in March).​

Mathematics
1 answer:
IRINA_888 [86]3 years ago
4 0
9/31 = 0.29 = 29%

Answer: 29%
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There are 24 children in a class, 16 brown-haired and 8 black-haired. Two students are randomly selected for a stage performance
Natali5045456 [20]
The answer is 7/69.

There are 8 black-haired children among 24 children. The probability of <span>randomly selecting black haired children for the first time is:
P1 = 8/24 = 1/3

Now, there are 7 black-haired children left among 23 children. The probability of </span>randomly selecting black haired children for the second time is:
P2 = 7/23

Since we want both of these events to occur together, we will multiply their probabilities:
P = P1 * P2 = 1/3 * 7/23 = 7/69
6 0
3 years ago
ERRE
Karo-lina-s [1.5K]

y-5

2y+ 1

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3 0
3 years ago
Complete the table for the given rule.<br> Rule: y = 6x-4<br> Please help
d1i1m1o1n [39]

y = 6x - 4

Substitute the given x values to solve for y.

x = 1:

y = 6(1) - 4

y = 6 - 4

y = 2

1 = 2

x = 3:

y = 6(3) - 4

y = 18 - 4

y = 14

3 = 14

x = 10:

y = 6(10) - 4

y = 60 - 4

y = 56

10 = 56

x                y

1                 2

3               14

10             56

5 0
3 years ago
Number 13 is what I need done
Nadusha1986 [10]
Instead of using an = sign we use \leq becuase its less than or equal to 100 dollars.

The equation of the line is y=10x+7

sub in 100 for y and the inequallity sign

10x+7\leq100

solve so x is isolated

10x\leq93
x\leq9.3

technically the answer is 9 because you cant buy a fraction of a CD
5 0
3 years ago
The polynomial $f(x)$ has degree 3. If $f(-1) = 15$, $f(0)= 0$, $f(1) = -5$, and $f(2) = 12$, then what are the $x$-intercepts o
Alex_Xolod [135]

Your calculator's cubic regression function can tell you the equation is

... f(x) = 2x³ + 5x² -12x = x(x +4)(2x-3)

The x-intercepts are -4, 0, +1.5.

_____

If you want to solve this "by hand", you can first of all recognize that since there is an x-intercept at 0, the cubic will only have three coefficients. That is, you can write the equation as

... f(x) = ax³ + bx² + cx

Substituting the given points (except (0, 0)) gives three linear equations in a, b, c.

... -a +b -c = 15 . . . . . for x=-1

... a + b + c = -5 . . . . for x=1

... 8a +4b +2c = 12 . . for x=2

adding the first two equations gives 2b=10, or b=5. Now, you can reduce the system to

... a + c = -10

... 4a +c = -4

Subtracting the first of these equations from the second gives 3a=6, or a=2. That tells you c=-12 (from a+c=10).

Then your equation is

... f(x) = x(2x² +5x -12)

Factoring by any of the usual techniques, or graphing, or using the quadratic formula will tell you the zeros (x-intercepts) are as above.

_____

Since the input values are sequential, you can also develop the function from differences of the output values. Those are 15, 0, -5, 12. First differences are -15, -5, +17. Second differences are +10, +22. The third difference is 12. Using the first of these differences in appropriate places in the interpolating polynomial formula, we have

... f(x) = 15 + (x+1)(-15 + (x)/2·(10 + (x-1)/3·(12))) = 2x³ +5x² -12x . . . . as above

4 0
3 years ago
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