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AleksandrR [38]
3 years ago
8

Can you write 0.02 in tenths

Mathematics
2 answers:
DENIUS [597]3 years ago
6 0
First you see how many zeroes there are. 2 right, now, which number has two zeroes? 100 has 2 zeroes so that definitely fits. So, you put 2 as the numerator and 100 as the denominator and that is how you convert it.
Dafna1 [17]3 years ago
5 0
In order to answer your question AND dissapoint you... :P
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It is impossible to write 0.02 in tenths.
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Let's review. 
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Let's say we have decimal 0.123.
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In decimal format...
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1 is the tenths place.
2 is the hundredths place.
3 is the thousandths place.
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And so on.
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So... unfortunately, you cannot write 0.02 in tenths.
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Answer:

2. n = 11

4. g = -2

6. t = 21

8. n = 4

10. y = -1

Step-by-step explanation:

2. 63  = -3(1 - 2n)

Dividing both the side by negative 3 we get

-21=1-2n\\2n=1+21\\2n=22\\n=\frac{22}{2} \\\therefore n=11

4. -g + 2(3 + g) = -4(g + 1)

First we will open the bracket by distributive property A( B +C) = AB + AC

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6.-3(t +5 ) + (4t + 2) = 8

Using distributive property A( B +C) = AB + AC we get

-3\times t + -3\times 5 + 4t + 2=8\\-3t-15+ 4t + 2=8\\t=8+15-2\\t=21\\\therefore t=21\\

8. -8 - n = -3(2n -4)

Using distributive property A( B +C) = AB + AC we get

-8 - n = -3\times 2n - -3\times4\\-8-n=-6n+12\\\textrm{all the n terms to the left inside and the constant of the right-hand side}\\6n-n=8+12\\5n=20\\n=\frac{20}{5}\\ \therefore n= 4

10. -4( 2 - y) + 3y = 3(y - 4)

Using distributive property A( B +C) = AB + AC we get

-4\times 2 --4\times y + 3y = 3\times y -3\times 4\\-8+4y+3y =3y-12\\\textrm{all the y terms to the left side and the constant to the right side}\\4y+3y-3y=-12+8\\4y=-4\\y=\frac{-4}{4}\\ \therefore y=-1

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3 years ago
41:41
Minchanka [31]

Answer:

Answer: B

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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