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3 years ago

9

Dave walked to his friend's house at a rate of 4mph and returned back biking at a rate of 10mph. If it took him 18 minutes longe

r to walk than to bike, what was the total distance of the round trip

1 answer:

schepotkina [342]3 years ago

4 0

Answer:

4 miles

Step-by-step explanation:

You might be interested in

NEED URGENT HELP

AnnyKZ [126]

Answer:

32.5

Step-by-step explanation:

If CED is 65, then AEB is 65, therefore we can calculate that CEA is 115 because 180 - 65 = 115. Then we do 180 - 115 = 65 which is the sum of angles ACE and CAE so 65 / 2 = 32.5 which is CAE.

Hope this helped!

8 0

3 years ago

What number could be a common denominator for these two fractions?<br> 3/10 and 1/5

Free_Kalibri [48]

Answer:

5 could be the common denominator

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The amount of energy it takes to lift a box might be a function of which of the following?

shtirl [24]

B. because it doesn't mater the shop but whats inside the box

6 0

3 years ago

Gambles are independent, and each one results in the playerbeing equally likely to win or lose 1 unit. Let W denote the netwinni

san4es73 [151]

Answer:

P{W>0}=0.5

P{W=0}=0.25

E{W}=0

Step-by-step explanation:

<u>Given:</u>

Gambles are independent i.e. each player is equally likely to win or lose 1 unit. OR each player has equal probability to win or lose 1 unit.

Let W denote the net winnings of a gambler whose strategy is to stop gambling immediately after his first win.

Then

<u>A.P{W>0}=?</u>

P{W>0}=0.5, because each player is equally likely to win or lose on first gamble. i.e there is equal chances for winning or losing on the first gamble.

<u>B.P{W<0}=?</u>

for P{W<0} we need to find P{W=0} first as;

P{W=0}=0.25

As there is equal probability to win or lose, after first win, if you want to finish gamble with no profit (equal number of lose and win) then if you losing, you have equal probability to win or lose so to finish your game with P=0 your probability is 0.25 (half of 0.5)

P{W<0} means net lose which is equal to total probability minus probability of profit and probability of net profit equal to zero.

i.e. P{W<0}=1-P{W=0}-P{W>0}

P{W<0}=1-0.25-0.5=0.25

<u>C.E{W}=?</u>

E{W}=P{W>0}*{W>0}+P{W<0}*{W<0}+P{W=0}*{W=0}

E{W}=0.5*(1)+0.5(-1)+0.25*(0) (for any value of W,P{W>0}*{W>0}+P{W<0}*{W<0}=0, because sum of same positive and negative numbers is zero)

E{W}=0

8 0

3 years ago

One year josh had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitche

Anna11 [10]

Answer:

Josh's ERA had a z-score of -3.26.

Alice's ERA had a z-score of -1.11.

Due to the lower z-score(ERA is a stat that the lower the better), Josh had a better year relative to his peers.

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Josh:

ERA of 2.89, mean of 5.083, standard deviation of 0.672. So

$X = 2.89, \mu = 5.083, \sigma = 0.672$ , and the z-score is:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2.89 - 5.083}{0.672}$

$Z = -3.26$

Josh's ERA had a z-score of -3.26.

Alice:

ERA of 3.31, mean of 4.032, standard deviation of 0.649. So

$X = 3.31, \mu = 4.032, \sigma = 0.649$ , and the z-score is:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{3.31 - 4.032}{0.649}$

$Z = -1.11$

Alice's ERA had a z-score of -1.11.

Which player had the better year relative to their peers, josh or alice ?

Due to the lower z-score(ERA is a stat that the lower the better), Josh had a better year relative to his peers.

8 0

3 years ago