Type the correct answer in the box log's

Mathematics

1 answer:

avanturin [10]2 years ago

4 0

Answer:

log(7) will be the correct answer.

Step-by-step explanation:

$\text{\frac{14}{3}}+\text{log}(\frac{11}{5})-\text{log}(\frac{22}{15})$ By using law of logarithm to solve the given expression,

1). $\text{log}(m)+\text{log}(n)=\text{log(mn)}$

2). $\text{log(m)}-\text{log(n)}=\text{log}(\frac{m}{n})$

By applying these rules, we can simplify the given expression,

$\text{log}(\frac{14}{3})+\text{log}(\frac{11}{5})-\text{log}(\frac{22}{15})$

$\text{log}(\frac{14}{3})+\text{log}(\frac{11}{5})-\text{log}(\frac{22}{15})=\text{log}(\frac{\frac{14}{3}\times \frac{11}{5}}{\frac{22}{15}})$

$=\text{log}(\frac{\frac{154}{15}}{\frac{22}{15}})$

= $\text{log}(\frac{154}{15}\times \frac{15}{22})$

= log(7)

Therefore, log(7) will be the correct answer.

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What is the equation of a circle whose center is begin ordered pair negative 4 comma 6 end ordered pair and whose radius is 9 cm

solong [7]

Answer:

$(x+4)^2+(y-6)^2=81$

Step-by-step explanation:

We want to find equation of a circle with center (-4,6) and radius 9cm.

The equation of a circle with center (h,k) and radius $r$ units is given by;

$(x-h)^2+(y-k)^2=r^2$

We substitute the radius and the center to obtain;

$(x+4)^2+(y-6)^2=9^2$

The required equation is:

$(x+4)^2+(y-6)^2=81$

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Makovka662 [10]

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<h3>What is a line of symmetry?</h3>

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