Answer:
Let two consecutive multiples of 3 be x and (x+3)
A/q,
x * (x+3) = 648
➡ x² + 3x = 648
➡ x² + 3x -648 = 0
➡ x² + 27x - 24x -648 = 0
➡ x ( x + 27 ) -24 ( x +27)
➡ ( x - 24) ( x + 27)
➡ x = 24 and x = -27
so, we take x = 24.
Required multiples of 3
➡ x = 24
➡ x +3 = 24+3 = 27.
ednocrkdlwmqcw e9rbeuopgjkmr qoejffwkf ,rwfrwfjr nmwrfHELP ME iuehf[eoiffkjkmfeiufkwjmfwufuStep-by-step explanation:
Answer:
Assume that the number is 100. Then, 20% of 100 is 20×100100 = 20. Increasing 100 by 20% means increasing 100 by 20 and the resultant number is 120.
