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RSB [31]
3 years ago
7

Amanda's car gets 27 miles per gallon. If her tank holds 22 1/2 gallons how many gmiles can she drive on one tank of gas

Mathematics
1 answer:
lianna [129]3 years ago
6 0
27 * 22.5 = 607.5 (or 607 1/2) miles
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Enter the y coordinate of the solution to this system of equations.
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-x-y=1
-y=1+x
y=-1-x

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-x=-2x+10
x=10

y=-1-10
y=-11
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3 years ago
A cone with volume 1350 m³ is dilated by a scale factor of 1/3.
ki77a [65]

Answer:

450

Step-by-step explanation:

You basically do 1350 * 1/3 or 1350/3

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4. The red graph (1) is the graph of f(x) = log(x). Describe the transformation of the blue function (2) and write the equation
sergey [27]

Answer:

Function f(x) is shifted 1 unit left and 1 unit up.

f(x)\rightarrow f(x+1)+1

Transformed function f(x+1)+1=\log(x+1)+1

Step-by-step explanation:

Given:

Red graph (Parent function):

f(x)=\log(x)

Blue graph (Transformed function)

From the graph we can see that the red graph is shifted 1 units left and 1 units up.

Translation Rules:

f(x)\rightarrow f(x+c)

If c>0 the function shifts c units to the left.

If c the function shifts c units to the right.

f(x)\rightarrow f(x)+c

If c>0 the function shifts c units to the up.

If c the function shifts c units to the down.

Applying the rules to f(x)

The transformation statement is thus given by:

f(x)\rightarrow f(x+1)+1

As function f(x) is shifted 1 unit left and 1 unit up.

Transformed function is given by:

f(x+1)+1=\log(x+1)+1

5 0
3 years ago
Ms. Moran has started an investment club at BSS. $8000 is invested, some at 10%
labwork [276]
The answer can be readily calculated using a single variable, x:

Let x = the amount being invested at an annual rate of 10%
Let (8000 - x) = the amount being invested at an annual rate of 12%

The problem is then stated as:

(x * 0.10) + ((8000 - x) * 0.12) = 900
0.10(x) + ((8000 * 0.12) - 0.12(x)) = 900
0.10(x) + 960 - 0.12(x) = 900
0.10(x) - 0.12(x) = 900 - 960
-0.02(x) = -60
-0.02(x) * -100/2 = -60 * -100/2
x = 6000 / 2
x = 3000

Thus, $3,000 is invested at 10% = $300 annually; and $8,000 - $3,000 = $5,000 invested at 12% = $600 annually, which sum to $900 annual investment.
6 0
3 years ago
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