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3 years ago

4(p-7)=44I wrote this question can you answer it

Mathematics

2 answers:

Keith_Richards [23]3 years ago

8 0

103.25

Step-by-step explanation:

rewrite

4p - 28 = 441

-28. -28

----- -----

0. 413

413÷4= 103.25

pav-90 [236]3 years ago

3 0

Answer:

p=117.25

Step-by-step explanation:

441/4=110.25

110.25+7=117.25

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What would you have to do to change 10 cubic feet into cubic inches? A. Multiply by 46,656 B. Divide by 1,728 C. Multiply by 1,7

Semmy [17]

1 foot = 12 inches

(1 foot)³ = (12 inches)³

12³ = 1,728 in³

To change 10 cubic feet into cubic inches

10 ft³ * 1728 in³/ft³ = 17,280 in³ Choice C. Multiply by 1,728

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3 years ago

Read 2 more answers

Mike saves $42 a week for 7 weeks. During his 8-day vacation, he plans to spend $8.25 each day for snacks. Which expression show

Alla [95]

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3 years ago

The hours of daylight, y, in Utica in days x from January 1, 2013 can be modeled by the equation y = 2.89sin(0.0145x-1.40) + 10.

Pie

Answer:

9.3 hours

Step-by-step explanation:

Given

$y = 2.89\sin(0.0145x-1.40) + 10.99.$

Required

Hours of sunlight on Feb 21, 2013

First, calculate the number of days from Jan 1, 2013 to Feb 21, 2013

$days = 52$

So:

$x = 52$

So, we have:

$y = 2.89\sin(0.0145x-1.40) + 10.99.$

$y = 2.89\sin(0.0145*52-1.40) + 10.99.$

$y = 2.89\sin(0.754-1.40) + 10.99.$

$y = 2.89\sin(-0.646) + 10.99.$

$y = 2.89*-0.6020 + 10.99.$

$y = -1.740 + 10.99.$

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$y = 9.3$ --- approximated

8 0

3 years ago

What are the x and y values....? -1x + 2y = 18 Haylp me pls!

Nesterboy [21]

Use the zeroes to figure this out... x=-18, y=9

7 0

3 years ago

A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar

Arisa [49]

Answer:

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

$n=17$ represent the sample selected

$\alpha=0.1$ represent the significance

$s^2 =4.7^2 =22.09$ represent the sample variance

$\sigma^2_0 =3.5^2 =12.15$ represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 = 12.15$

Alternative hypothesis: $\sigma^2 \neq 12.15$

The statistic for this case is given by:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

The degrees of freedom are:

$df =n-1= 17-1=16$

$\chi^2 =\frac{17-1}{12.15} 22.09 =15.87$

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates $\alpha/2 =0.05$ of the area on each tail and we got:

$\chi^2_{crit}= 7.962$

$\chi^2_{crit}=26.296$

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

$p_v =2*P(\chi^2 >15.87)=0.92$

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0

3 years ago

4(p-7)=44I wrote this question can you answer it ​

4(p-7)=44I wrote this question can you answer it