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Naily [24]
3 years ago
8

AN SOMEONE PLEASE HELP ME SOLVE THIS!!

Mathematics
1 answer:
stepan [7]3 years ago
3 0

A) Scale factor:

Divide 2 congruent sides:

24 / 36 = 0.667

From PQR to XYZ is a 0.667  (2/3 as a fraction) scale factor.

B) Volume = (1/2 x base x side) x height:

Volume = 1/2 * 36 x 48 = 864 * 15 = 12,960 cubic inches.

C) Find the height of the prism:

7776 = (1/2 * base * sides) x height

7776 = (1/2 x 36 x 48) * height

7776 = 864 * height

Height = 7776 / 864 = 9 inches.

The scale factor is 2/3, the height of XYZ = 2/3 *9 = 6 inches.

Volume of XYZ = 1/2 x 24 x 32 = 384 x 6 = 2,304 cubic inches.

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Step-by-step explanation:

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Multiply 3 * 3 to get 9. So each side is 3 feet.

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One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
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Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

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Hello!

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Use the Pythagorean Theorem to solve for the hypotenuse:

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