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3 years ago

Help me on this problem

Mathematics

1 answer:

Wittaler [7]3 years ago

3 0

Answer:

1 and 3 are both perpendicular to segment NY

Step-by-step explanation:

1. Find the slope of line NY

slope of NY = 5-(-7)/-11-5 = - 3/4

Any line that is perpendicular to NY should have a slope of the inverse of negative slope of NY.

2.Find the slope of perpendicular lines

the inverse of negative slope of NY = - (-4/3) = 4/3

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Answer:believe it’s 12

Step-by-step explanation:

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3 years ago

Work out the area of the circle and leave it in cm plz

Marat540 [252]

Answer:

132.7495 cm^2

Step-by-step explanation:

area of circle=πr^2

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6.5^2

42.25

42.25*3.142

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2 years ago

Read 2 more answers

Given loga (m) = 10 and loga (n) = 25 , find loga (m * n ^ 2)

mina [271]

The result of the log function $log_a (m * n ^ 2)$ is 60

According to the law of logarithm if $log_ab=y$ then $b=a^y$

Given the following expressions

$log_am=10\\log_an=25$

This can be expressed as

$m =a^{10} \ and \ n = a^{25}$

Substitute the value of m and n into the expression $log_a (m * n ^ 2)$ to have:

$log_a (m * n ^ 2) = log_a(a^{10}\times a^{50})\\=log_aa^{60}\\=60log_aa\\=60(1) \\= 60$

This shows that the result of the log function $log_a (m * n ^ 2)$ is 60

Learn more here: brainly.com/question/12049968

6 0

2 years ago

In a certain test, the number of successful candidates was three times than that of unsuccessful candidate, if there had been 16

Natali5045456 [20]

Answer:

The number of candidates is 136.

Step-by-step explanation:

3 0

3 years ago

Find the first five terms of each geometric sequence described <br><br> A1=1 R=4

xenn [34]

$\bf n^{th}\textit{ term of a geometric sequence}
\\\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
r=\textit{common ratio}\\
a_1=\textit{first term}\\
-------\\
a_1=1\\
r=4
\end{cases}\\\\
-----------------------------\\\\
$

$\bf \begin{array}{ccllll}
term&value\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
1&a_1=1\\
2&a_2=a_1\cdot 4^{2-1}\\
3&a_3=a_1\cdot 4^{3-1}\\
4&a_4=a_1\cdot 4^{4-1}\\
5&a_5=a_1\cdot 4^{5-1}\\
\end{array}$

3 0

3 years ago