Question

What is the value of x?

Answer 1

A^2+B^2=c^2 for a right triangle
In this case x is a, b is 8 and c is 14 plug in
X^2= 14^2-8^2
X^2=132
X=11.48
X=11.5

Answer 2

ANSWER

$x = 11.5$
EXPLANATION

Triangle ABC is a right angle triangle.

We can apply the Pythagorean Theorem to get,

${x}^{2} + {8}^{2} = {14}^{2}$

We now solve for x to get,

${x}^{2} = {14}^{2} - {8}^{2}$
The right hand side is difference of two squares, this factors to give us,

${x}^{2} = (14 - 8)(14 + 8)$

${x}^{2} = 6 \times 22$

${x}^{2} = 132$

We take the positive square root of both sides to obtain,

$x = \sqrt{132}$

$x = 11.48$

$x = 11.5$