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Lunna [17]
2 years ago
7

What is -3x-5 = 16 I'm stuck on a simple problem

Mathematics
2 answers:
Zepler [3.9K]2 years ago
5 0

Answer:

x=-7

Step-by-step explanation:

-3x-5=16

Add 5.

-3x=21

Divide by -3.

x=-7

mariarad [96]2 years ago
4 0

Answer:

-7

Step-by-step explanation:

-3x-5=16

-3x-5+5=16+5

-3x=21

-3x/-3=21/-3

x=-7

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2. Write an equation of the line that passes through the<br> points (1,3) and (-1,1).
cestrela7 [59]

Answer:

I've been trying to figure this out with out a chart and i keep confusing myself

Step-by-step explanation:

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3 years ago
Why it take much longer time ghan the time calculated
mrs_skeptik [129]

Answer:

for what bro

Step-by-step explanation:

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3 0
2 years ago
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How many ways can Carlos choose 2 pizza toppings from a menu of 4 toppings if each topping can only be chosen once?
Ahat [919]

Answer:

30 different ways

Step-by-step explanation:

Hi

for the first topping she can choose 1 of 6 items

so she has 6 choices

and then the second topping she has 5 choices as each topping can only be chosen once

so it comes 6 * 5 = 30

3 0
3 years ago
At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

As we know the poisson process, we get that

P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%

Hence, a) 4.6798, and b) 19.8%.

7 0
3 years ago
(4x-5)+2(3x+1)<br> Can you help me solve this plz for me
Korvikt [17]

Answer:

10x - 3

Step-by-step explanation:

First, distribute 2 to all terms within the second parenthesis:

2(3x + 1) = (2 * 3x) + (2 * 1) = 6x + 2

4x - 5 + 6x + 2

Combine like terms (terms with the same amount of variables).

4x + 6x + 2 - 5

(4x + 6x) + (2 - 5)

10x + (-3)

10x - 3

10x - 3 is your answer.

~

8 0
3 years ago
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