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Gwar [14]
3 years ago
11

I need some help quickly only til 12:00 AM CST

Mathematics
1 answer:
wel3 years ago
4 0

Answer:

First statement correct

Second statement not correct

You did it correctly though

Step-by-step explanation:

Since the lines have have same slope they would be parallel lines and never intersect each other hence inconsistent solution hence the first statement is correct.

A system of linear equations in which the two equations represent the  same line; there are an infinite number of solutions to a dependent system, but these lines don't overlap each other hence no infinitely many solution thus not a dependent system and hence not correct

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5) Select the best method to solve the system.
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5 0
3 years ago
BRAINLIEST! HELP! Please help me! I NEED PART D AND E! I’m so lost :(
Zinaida [17]

Part A

Given:

Volume of square pyramid = 73.5 <u>cubic</u> inches

height of square pyramid = 4.5 inches

To find:

1)Side length of square pyramid.

2)if side length of square pyramid is rational or irrational

Steps:

1) Side length = \sqrt{\frac{3v}{h} }

Side length = \sqrt{\frac{3*73.5}{4.5} }

Side length = \sqrt{\frac{3*73.5*10}{4.5*10} }         (multiplying both sides to make it a whole number)

Side length = \sqrt{\frac{3*735}{45} }

Side length = \sqrt{\frac{735}{15} }                  (3 gets canceled out)

Side length = \sqrt{49}

Side length = 7 inches

Therefore, the side length of the square pyramid is 7 inches long

2) 7 is a rational number, so the side length of the square pyramid is a rational number.

It is a rational number because,

it can be written in the form p/q,  where

1) q \neq0

2) p and q are co-prime

3) p and q are integers

Part B

Given:

Volume of Khafre's pyramid = 9/10 of Khufu's pyramid's volume

Volume of Kristina's first pyramid = 73.5 cubic inches

To find:

Volume of Kristina's second pyramid

Steps:

Volume of Kristina's second pyramid = 9/10 the volume of Kristina first pyramid

Volume of second pyramid = \frac{9}{10}*73.5

Volume of second pyramid = 9 * 7.35

Volume of second pyramid = 66.15 cubic inches

The volume of the second pyramid should be 66.15 cubic inches

Part C

Given:

Height of pyramid = 4.41 inches

Volume of pyramid = 66.15 cubic inches

To find:

1) Side length of pyramid

2) if the side length is rational or irrational

Steps:

1) Side length = \sqrt{\frac{3v}{h} }

Side length = \sqrt{\frac{3*66.15}{4.41} }

Side length = \sqrt{\frac{3*66.15*100}{4.41*100} }         (multiplying both sides to make it a whole number)

Side length = \sqrt{\frac{3*6615}{441} }

Side length = \sqrt{\frac{6615}{147} }                   (3 gets canceled)

Side length = \sqrt{45}

Side length of pyramid is \sqrt{45} inches

2) \sqrt{45} cant be written in the form of a fraction, so it is an irrational number

(if u want i can explain this more)

Part D

Given

Height of model pyramid = 4.5 inches

Height of Khufu's pyramid = 755.75 feet (had to search the internet for the answer, so I am not sure if it is correct)

Side length of model pyramid = 7 inches

Side length of Khufu's pyramid = 481.4 feet (had to search the internet for the answer)

To find:

1)If the model is to scale with Khufu's pyramid

2) If the model is close to scale with Khufu's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model

Ratio = 4.5 in : 7 in

         = 45 : 70

         = 9 : 14

         = 0.6428

Now lets find the ratio of the height to the side length of Khufu's pyramid

Ratio = 481.4 feet : 755.75 feet

         = 5776.8 in : 9069 in

         =  0.6369

Therefore the model is not to scale with Khufu's pyramid

2) Yes the scale is close

Part E

Given:

Height of model pyramid = 4.41 inches

Height of Khafre's pyramid = 448 feet

Side length of model pyramid = \sqrt{45} inches

Side length of Khafre's pyramid = 706 feet

To find:

1) If the model is to scale with Khafre's pyramid

2) If the model is close to scale with Khafre's pyramid

Steps:

1) First lets find the ratio of the height to the side length of the model pyramid,

Ratio = 4.41 in : \sqrt{45} in

= 4.41 : 6.7082

= 0.6574

Now lets find the ratio of the height to the side length of Khafre's pyramid

Ratio = 448 ft : 706 ft

= 5376 in : 8472 in

= 0.6345

Therefore the model is not to scale with Khafre's pyramid

2) No, the model is not close to scale,  (it depends by what is meant by close, for me its 0.01)

Happy to help, and I hope you learnt something from this answer that will help you in the future

If you didn't understand any topic pls ask

3 0
3 years ago
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