<span>Your bowl contains 8 red balls, and 9 blue balls, and you draw 4 balls. in how many ways can the selection be made so that at least one of each color is drawn.</span>
Call the notebooks x, and the pencils y.
<span>3x + 4y = $8.50 and 5x + 8y = $14.50 </span>
<span>Then just solve as simultaneous equations: </span>
<span>3x + 4y = $8.50 </span>
<span>5x + 8y = $14.50 </span>
<span>5(3x + 4y = 8.5) </span>
<span>3(5x + 8y = 14.5) </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 24y = 43.5 </span>
<span>Think: DASS (Different Add, Similar Subtract). 15x appears in both equations so subtract one equation from the other. Eassier to subtract (15x + 20y = 42.5) from (15x + 24y = 43.5) </span>
<span>(15x + 24y = 43.5) - (15x + 20y = 42.5) = (4y = 1) which means y = 0.25. </span>
<span>Then substitue into equation : </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 5 + 42.5 </span>
<span>15x = 42.5 - 5 = 37.5 </span>
<span>15x = 37.5 </span>
<span>x = 2.5 </span>
<span>15x + 24y = 43.5 </span>
<span>15(2.5) + 24(0.25) </span>
<span>37.5 + 6 = 43.5 </span>
<span>So x (notebooks) are 2.5 ($2.50) each and y (pencils) are 0.25 ($0.25) each.</span>
Answer:
wait so are you adding or
Answer:
Diameter of a circle = 1.6 Cm
Step-by-step explanation:
Given:
Distance between first and third coins = 3.2 cm
Find:
Diameter of the coins = ?
Computation:
Number of circle = 3
In the given figure,distance between the first and third coins is 3.2 cm.
So,
Distance = 1st circle radius + 2nd circle diameter + 3rd circle radius
Distance = 1st circle radius + 2 (radius) + 3rd circle radius
Distance = R + 2R + R
3.2 Cm = 4 R
Radius = 0.8 Cm
Diameter of a circle = 2 × radius
Diameter of a circle = 2 × 0.8
Diameter of a circle = 1.6 Cm
We have slope intercept form. Parallel means the same slope, and we get to choose the intercept to fit the new point (-6,0).
y = (1/3) x + b
0 = (1/3) (-6) + b
2 = b
Answer y = (1/3) x + 2 third choice
