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Paraphin [41]
3 years ago
8

Breanne is trying to decide which of her two friends to invite over Friday night for her birthday party. She writes all three of

their names on slips of paper and places them in a bag. Breanne will draw one name and then draw another name. Is this an example of an independent or dependent event?
A. This is an example of a independent event because she draws a name and does not place it back into the bag.
B. This is an example of a dependent event because she draws a name and does not place it back into the bag.
C. This is not an independent or dependent event because she should let all three of her friends come to the party.
D. none of the above
Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Because she doesn't put it back in the bag.

anzhelika [568]3 years ago
7 0
I’d go with B !!!!!!!!
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6 0
3 years ago
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How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t
Zarrin [17]

By first principles, the derivative is

\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h

Use the binomial theorem to expand the numerator:

(x+h)^n=\displaystyle\sum_{i=0}^n\binom nix^{n-i}h^i=\binom n0x^n+\binom n1x^{n-1}h+\cdots+\binom nnh^n

(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

The first term is eliminated, and the limit is

\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h

A power of h in every term of the numerator cancels with h in the denominator:

\displaystyle\lim_{h\to0}\left(nx^{n-1}+\dfrac{n(n-1)}2x^{n-2}h+\cdots+nxh^{n-2}+h^{n-1}\right)

Finally, each term containing h approaches 0 as h\to0, and the derivative is

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4 0
3 years ago
Please help! Find the x-intercepts of the parabola with vertex (-4, 2) and y-intercept (0, -30). Write your answer in this form:
ch4aika [34]
X1-y1
x2-y2

-4-3
0+30

-6
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the answer would be -0.2
6 0
3 years ago
I'll give points and brainalist for answer / explanation
Valentin [98]

Answer:

D. 8

Step-by-step explanation:

C= 2πr

π= 3.14

C= 25.12

25.12 = 2 * 3.14 * r

r= 4

d= 2r

d= 8

5 0
3 years ago
a toy store marks down every toy by 15% in January. How much does a toy cost during January? Use p for the price in December.
satela [25.4K]

A toy cost 0.85p in January.

Step-by-step explanation:

Given,

Mark down in January = 15%

Let,

Price in December = p

Mark down in January = 15% of price in December

Mark down in January = \frac{15}{100}*p

Mark down in January = 0.15p

Price of toy in January = Price in December - Mark down

Price of toy in January = p - 0.15p = 0.85p

A toy cost 0.85p in January.

Keywords: mark down, subtraction

Learn more about subtraction at:

  • brainly.com/question/1993757
  • brainly.com/question/2048256

#LearnwithBrainly

7 0
3 years ago
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