Complete each statement then state the property or properties illustrated by each statement on
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The equation of a circle is
(x-h)² + (y-k)² = r²
for center (h, k) and radius r. Of course, the radius can be computed by putting the point in the equation.
(x-2)² + (y-3)² = (-1-2)² + (1-3)² = 9+4 = 13
The standard equation of the circle is (x-2)² + (y-3)² = 13.
(x-h)² + (y-k)² = r²
for center (h, k) and radius r. Of course, the radius can be computed by putting the point in the equation.
(x-2)² + (y-3)² = (-1-2)² + (1-3)² = 9+4 = 13
The standard equation of the circle is (x-2)² + (y-3)² = 13.
assuming
Then the column values for base five here are
5³ 5²
We can get 1 × 5³ = 125 → 219 - 125 = 94
We can get 3 × 5² = 75 → 94 - 75 = 19
We can get 3 x → 19 - 15 = 4
and 4 = 4 ×
Thus =
As a check
(1 × 125 ) + (3 × 25 ) + (3 × 5 ) + 4 = 219