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photoshop1234 [79]
3 years ago
12

Arrange the Jumbled letters 1.eilf ngrihsa ________________ 2.cersityu ourreecs ________________ 3. ngrihsa ________________ 4.

mmocnoitacin ________________ 5. exiflble ecscsa
Computers and Technology
1 answer:
Alisiya [41]3 years ago
5 0

Answer:

1. file sharing

2. security recourse

3.sharing

4.communication

5.flexible access

Explanation:

-

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The sheep in the image below is an example of which of the following?
n200080 [17]

Answer:

balanced space.

Explanation:

This is a edu guess.

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2 years ago
Most simple computer programs follow the basic pattern defined by the acronym IPO. What does IPO mean with regards to programmin
Art [367]

Answer:

IPO means Input - Process - Output

Explanation:

The IPO model means that a computer program is given an input to process, it processes the given input and return an output as the result.

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To what health hazard are people working in offices most likely to be exposed.
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3 years ago
What does the following code print?double[] myList = {1, 5, 5, 5, 5, 1};double max = myList[0];int indexOfMax = 0;for (int i = 1
Liula [17]

Answer:

This code will print: 4

Explanation:

Following is the step-by-step explanation for the given code:

  • Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:

                    double[] myList = {1, 5, 5, 5, 5, 1};

  • Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).

                 double max = myList[0];  

  • A variable indexOfMax having datatype int will be initiated as 0.

                 int indexOfMax = 0;

  • Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.

                    for (int i = 1; i < myList.length; i++)

                            { if (myList[i] >= max)

                               { max = myList[i];

  • Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).

                  indexOfMax = i; }}

  • At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.

              System.out.println(indexOfMax);

i hope it will help you!

7 0
3 years ago
Please please help me
Sholpan [36]

Answer:

increase your browser security settings

8 0
2 years ago
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