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Lina20 [59]
3 years ago
10

Write the definition of a function named newbie that receives no parameters and returns true the first time it is invoked (when

it is a "newbie"), and that returns false every time that it is invoked after that.
Computers and Technology
1 answer:
kondaur [170]3 years ago
7 0

Answer:

The function definition to this question can be described as follows:

bool newbie() //defining a bool method newbie

{

static bool y = true ; // defining a static bool variable y and assign value true

bool t1=y; //defining bool variable t1 and assign value of variable y

y=false; // assigning value in variable y

return t1; // return value of variable t1

}

Explanation:

The program to this question can be described as follows:

Program:

#include <iostream> //defining header file

using namespace std;

bool newbie() //defining a bool method newbie

{

static bool y = true ; // defining a static bool variable y and assign value true

bool t1=y; //defining bool variable t1 and assign value of variable y

y=false; // assigning value in variable y

return t1; // return value of variable t1

}

int main() //defining main method

{

int s,s1; //defining integer variable s,and s1

s=newbie(); // variable s that call method

cout<<s<<endl; //print value

s1=newbie();//variable s that call method

cout<<s1;  //print value

return 0;

}

Output:

1

0

Description:

The description of the above function can be described as follows:

  • In the above method definition a boolean method "newbie" is declared, which can't accept any parameters, inside the method, two boolean variable "y and t1" is declared.
  • In this variable, variable y is a static boolean variable, that assigns a true value, and in t1 variable, we hold static variable value.  
  • In the next step, the "y" variable assigns a value, that is false and returns variable t1 value.
  • In the next step, the main method is declared, inside these two integer variable s, s1 is declared, that calls a method, and prints it value in the first time, it will print 1, that means the false and second time it will print 0, that means false.
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Answer:

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Explanation:

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Use JavaWrite a program that will simulate a change machine found at cash registers. Input the amount due and amount paid from t
Ksju [112]

Answer:

Here is the JAVA program:

import java.util.Scanner;  //to accept input from user

public class Main { // class name

 public static void main(String [] args) {  // start of main method

   Scanner input = new Scanner(System.in);  // creates Scanner class object to take input from user

   System.out.println("Please Enter the Cost of the Item: ");  // prompts user to enter the cost of item

   double itemCost = input.nextDouble();  //scans and reads the input value of item cost

   System.out.println("Please Enter the Amount Paid: ");  // prompts user to enter the amount paid

   double amount = input.nextDouble();  //scans and reads the value of amount from user

   int change = (int)(amount * 100 - itemCost * 100);  //compute the remaining amount i.e. change

   System.out.println("Change Owed: " + change / 100.0);  // displays the owed change

   int quarters = change / 25;  // computes the value for quarters

   change = change % 25;  // compute the quarters remaining

   int dimes = change / 10;  //  computes dimes

   change = change % 10;  //  computes dimes remaining

   int nickels = change / 5;  // computes nickels

   change = change % 5;  // compute nickels remaining

   int pennies = change;  // computes pennies

   System.out.println("Quarters: " + quarters);  // displays computed value of quarters

   System.out.println("Dimes: " + dimes);  // displays value of dimes

   System.out.println("Nickels: " + nickels);  // displays value of nickels

   System.out.println("Pennies: " + pennies);   }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

            = 500 - 457

change = 43

Now the change owed is computed as:

change / 100.0 = 43/100.0 = 0.43

Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

   change = change % 25;

This becomes:

   change = 43 % 25;

  change = 18

Next the dimes are computed from remaining value of change as:

dimes = change / 10;

dimes = 18 / 10

dimes = 1

Now the remaining is computed as:

   change = change % 10;

This becomes:

   change = 18 % 10

  change = 8

Next the nickels are computed from remaining value of change as:

nickels = change / 5;

nickels = 8 / 5

nickels = 1

Now the remaining is computed as:

   change = change % 5;

This becomes:

   change = 8 % 5

  change = 3

At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43                                                                                                                Quarters: 1                                                                                                                      Dimes: 1                                                                                                                         Nickels: 1                                                                                                                       Pennies: 3  

The screenshot of the output is attached.

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3 years ago
What is the highest numeral in a binary code?
Anarel [89]

Answer:

The highest numeral in binary code is 1

In binary, you can only have 1s and 0s

if you're asking for the biggest number that can be represented, it's 255, which is 11111111. (this is 8 1s)

Explanation:

Is this a trick question? lol

May I have brainliest please? :)

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Suppose you are an ISP that owns a / 22 IPv4 address block. Can you accommodate requests from six customers who need addresses f
lisabon 2012 [21]

Answer:

It is not possible.

Explanation:

In this example, we need to accommodate 473 computers for six clients that are 473 IP addresses.

For this request just we have /22 IPv4 address blocks, this mean

22 red bits 11111111111111111111110000000000 <--- 10 host bits

We must increase red bits to 25, we need these 3 bits to create 6 sub red, in this case, 2^3 = 8 sub red.

Why did we ask 3 bits? Because if we ask only 2, 2^2 = 4, and we need 6 sub red.

25 red bits 11111111111111111111111110000000 7 host bits

In this case, we need more than 260 computers, but just we have 7 bits, this means.

2^7 = 128 and just one customer needs 260, for that is impossible.

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3 years ago
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