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klio [65]
3 years ago
14

Is ( -1,5 ) a solution to the equation 2x+5y=0 Why or Why not?​

Mathematics
1 answer:
icang [17]3 years ago
5 0

Answer:

No, that is not a solution

Step-by-step explanation:

Plug in the numbers to their respective values, so -1 to x, and 5 to y.

2(-1) + 5(5) = 0

-2 + 25 = 0

23 = 0?

No, that is not a solution

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The regular price of a watch is $28.25. During a sale, the watch was marked 12% off. What was the price of the watch during the
zalisa [80]

Answer:

I believe the answer would be D, $24.86

4 0
3 years ago
You measure 50 textbooks' weights, and find they have a mean weight of 37 ounces. Assume the population standard deviation is 5.
Hoochie [10]

Answer:

90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

Step-by-step explanation:

We are given that you measure 50 textbooks' weights, and find they have a mean weight of 37 ounces.

Assume the population standard deviation is 5.2 ounces.

Firstly, the Pivotal quantity for 90% confidence interval for the population mean is given by;

                           P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean weight = 37 ounces

           \sigma = population standard deviation = 5.2 ounces

           n = sample of textbooks = 50

           \mu = true population mean textbook weight

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

<u></u>

<u>So, 90% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5%

                                            level of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X -1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X +1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                          = [ 37-1.645 \times {\frac{5.2}{\sqrt{50} } } , 37+1.645 \times {\frac{5.2}{\sqrt{50} } } ]

                                          = [35.79 , 38.21]

Therefore, 90% confidence interval for the true population mean textbook weight is [35.79 ounces , 38.21 ounces].

7 0
3 years ago
Please help me ASAP please
Maksim231197 [3]

Answer:

the bottom is kinda blurry

4 0
3 years ago
Find the volume and round to the nearest hundredths if you need too
strojnjashka [21]

Answer:

615.75 inches

Step-by-step explanation:

The formula to find the volume of a cylinder is:

v = \pi \:  {r}^{2} h \\ \pi \:  \times  {7}^{2}  \times 4 \\ v = 615.75

Hope this helps!!

8 0
3 years ago
Estimate the quotient 9.13 divided by 42
IgorLugansk [536]

Answer:

I would say 2.3 possibly

Plz mark brainliest

Step-by-step explanation:

3 0
3 years ago
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