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Sergeu [11.5K]
3 years ago
6

Homework help due today!!

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer: D

Step-by-step explanation:

It's not iscolses or equal length

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Which of the following is NOT a requirement of testing a claim about a population proportion using a formal method of hypothesis
Pie

Answer:

A. The lowercase​ symbol, p, represents the probability of getting a test statistic at least as extreme as the one representing sample data and is needed to test the claim.

Step-by-step explanation:

The conditions  required for testing  of a claim about a population proportion using a formal method of hypothesis​ testing are:

1) The sample observations are a simple random sample.

2) The conditions for a binomial distribution are satisfied

3) The conditions np5 and nq5 are both satisfied. i.e n: p≥ 5and q≥ 5

These conditions are given in th options b,c and d.

Option A is not a condition for testing  of a claim about a population proportion using a formal method of hypothesis​ testing.

8 0
3 years ago
Something divided by - 1 1/4 = 2.8
sergey [27]
-3 1/2 because if you do 2.8 times 1 and 1/4 you get 3.5 and 3.5 as a fraction is 3 1/2
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3 years ago
Read 2 more answers
o eliminate the y terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before add
Anna71 [15]

Answer:

Look at your answers for the last question in all four sets. Locate these four elements on the periodic table.  Enter the name of the group that all four elements belong to.  Watch your spelling!  [Hint:  If all four answers for the last question are not in the same group on the periodic table, redo your sets or contact your instructor.]

A screen reader friendly version of the periodic table (opens in a new window) is available, as well as a printable, black and white version (opens in a new window).

Step-by-step explanation:

7 0
2 years ago
When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occu
oee [108]

Answer:

a. 135 g

b. 60.6 min

Step-by-step explanation:

a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.

The chemical equation for the reaction is given below

Cu²⁺(aq) + 2e⁻ → Cu(s)

We find the number of moles of Cu that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = ‭14,400‬ s

So, n = It/F = 28.5 A × ‭14,400‬ s/96485 C/mol = ‭410,400‬ C/96485 C/mol = 4.254 mol

Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu

Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol

So, m = n'M

= 2.127 mol × 63.546 g/mol

= 135.15 g

≅ 135 g to 3 significant figures

b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?

The chemical equation for the reaction is given below

Au⁺(aq) + e⁻ → Au(s)

We need to find the number of moles of Au in 37.1 g

So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol

So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol

Since 1 mol of Au is deposited  by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons

We find the time it takes to deposit 0.188 mol of electrons that are deposited from

nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time

So, t = nF/It

= 0.188 mol × 96485 C/mol ÷ 5.00 A

= ‭18173.30‬ C/5.00 A

= 3634.66 s

= 3634.66 s × 1min/60 s

= 60.58 min

≅ 60.6 min to 3 significant figures

6 0
3 years ago
What expression is quadratic monomial?
grandymaker [24]

Answer:

the solution is x^4. the second one

7 0
3 years ago
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