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Tresset [83]
3 years ago
12

If a migrating hawk travels m mph in still​ air, what is its rate when it flies into a steady headwind of 3 3 ​mph? what is its

rate with a tailwind of 6 6 ​mph
Mathematics
2 answers:
myrzilka [38]3 years ago
7 0
<span>Headwind of 4 mph: m-4

(Since the headwind is going against the hawk, the hawk should be slower. You subtract 4 from the speed, which in this case is the variable M)

Tailwind of 6 mph: m+6

(Since the tailwind is going with the hawk, the hawk should be faster. You add 6 to the speed, which is in this case is the variable M)

</span>
Alexxx [7]3 years ago
6 0

Answer:

The Rate when hawk flies into a steady headwind is m-3 and rate when hawk flies into a steady tailwind is m + 6.

Step-by-step explanation:

As given

If a migrating hawk travels m mph in still​ air .

As  migrating hawk  when it flies into a steady headwind of 3 ​mph .

As the headwind is travelling against migrating hawk files thus the migrating hawk speed become slower .

Thus

Rate when hawk flies into a steady headwind = migrating hawk speed in still​ air - Headwind speed

Rate when hawk flies into a steady headwind = m - 3

As given

As  migrating hawk  when it flies into a steady tailwind of 6 ​mph .

As the tailwind is travelling with the migrating hawk files thus the migrating hawk speed become faster .

Thus

Rate when hawk flies into a steady tailwind = migrating hawk speed in still​ air + tailwind speed

Rate when hawk flies into a steady tailwind = m + 6

Therefore the Rate when hawk flies into a steady headwind is m-3 and rate when hawk flies into a steady tailwind is m + 6.




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Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
4 years ago
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