Vertex form is basically commplete the square
y=a(x-h)^2+k
y=x^2+14x+4
take 1/2 of 14 and square it, (7^2=49)
add that and its negative to right side
y=x^2+14x+49-49+4
factor perfect squaer
y=(x+7)^2-49+4
y=(x+7)^2-45
answer is A
Answer:
42 because 3 tens is 30 and 12 ones is 12. so you do 30 + 12 = 42
I am legit doing this in school but I don't know it lol
Answer:
The correct answer is c = -8/3.
Step-by-step explanation:
The first step in solving this problem would be to simplify by combining like terms on the left side of the equation.
6c - 8 - 2c = -16 + c
4c - 8 = -16 + c
Then, we can subtract c from both sides of the equation to get rid of the positive c on the right side of the equation.
4c - c - 8 = -16 + c - c
3c - 8 = -16
Next, we can add 8 to both sides of the equation.
3c - 8 + 8 = -16 + 8
3c = - 8
Then, we can divide both sides of the equation by 3.
c = -8/3
Hope this helps!
Best way I would say is to graph both lines and see if they are parallel to eachother
