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3 years ago

Pretty ez ngl but need help extra points

Mathematics

2 answers:

VLD [36.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

Amy spent 1/6 of the 90 dollars on school supplies, which means to multiply 1/6 by 90

1/6*90

6 and 90 are both factors of 3, so cancel

1/2*30

30/2

$15

Answer is D

PS. you can put the fraction 15/90 and see that it is equal to 1/6 if you're not sure/ if you want to double check :)

baherus [9]3 years ago

5 0

Answer:

Concept: Algebraic Manipulation

90* 1/6 = 15
Hence its 15 dollars
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Read 2 more answers

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

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