Remember that the general formula for a circle is <span>
(x – h)</span>² + (y – k)² = r²<span>, where (h,k) is the coordinate of the center.
We already know that (h,k) = (5,-4), since we know the center's coordinates. We need to find r, the radius, using the distance between the center and the point (-3,2).
To do this, we can either use the distance formula, or plug in the points in our circle equation and solve for r.
Let's do the second one, plugging in and solving for r.
We can use the point (-3,2) for (x,y):
</span>(x – h)² + (y – k)² = r²
(-3 - 5)² + (2 - -4)² = r²
(-8)² +(6)² = r²
64 + 36 = r²
100 = r²
r = 10
We know that r=10, and that r² = 100
Using h, k, and r, we can now solve for the equation of the circle in standard form.
The equation of the circle is:
(x – 5)² + (y + 4)² = 100
Answer:
False
Step-by-step explanation:
Bc I literally just took that quiz and it's false
Answer:
A=10 cm
B=5 cm
Area of square = 25 cm
Step-by-step explanation:
Since that is an equilateral triangle based off the fact that all the sides are the same variable (a) then that means 30 divided by 3 which equals 10. So now we know that a = 10. Lets input that information for the rectangle. Since there are 2 a's that equals 20 and the perimeter is 30 so b has to be 5 since 5 times 2 is 10 plus 20 equals 30. so now we know that a=10 and b=5 so our squares sides are all 5. The area of the square is 25
The function is stretched vertically by a factor of 3.
The function shifts 2 to the right.
The function is moved 5 units up.
Explanation:
The parent function of the graph is 
The transformation for the parent function is given by 
Thus, the transformed function is in the form of 
where a is the vertical compression/stretch,
h moves graph to left or right and
k moves the graph up or down.
Thus, from the transformed function , we have,
The attached graph below shows the transformation of the graph that the graph is stretched vertically by a factor of 3 and shifted 2 units to the right and moved 5 units up.
Hence, The function is stretched vertically by a factor of 3.
The function shifts 2 to the right.
The function is moved 5 units up.
