2 years ago

20 points!on friday, 0.325 of the students in lola's math class were absent. what percent of the class were absent

Mathematics

1 answer:

Dmitry [639]2 years ago

3 0

How much students were there in the beginning

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Find the tangent plane to the given surface of f(x,y)=6- 6/5 x-y at the point (5, -1, 1). Make sure tat your final answer for th

HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

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3 years ago

Determine whether the following sequence is geometric. If so, find the common ratio.

Shtirlitz [24]

Answer:

a) r = 5

b) false

Step-by-step explanation:

study about GP

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3 years ago

I will mark branliest if correct

n200080 [17]

Answer:

The answer is: y = - |x+1|+1

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2 years ago

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The answer plz I will thank u

Darya [45]

2x3= 6
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3 years ago

4.) v = 3k<br>Solve for t

qaws [65]

The whole thing flips around and ends up being t = 3k/?

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3 years ago