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Romashka [77]
3 years ago
13

20 points!on friday, 0.325 of the students in lola's math class were absent. what percent of the class were absent

Mathematics
1 answer:
Dmitry [639]3 years ago
3 0
How much students were there in the beginning
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What is the value of x?
liq [111]
An exterior angle is equal to the sum of the 2 non adjacent angles. In this case

100 = x + 70 Subtract 70
x = 100 - 70
x = 30
6 0
3 years ago
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Help please word problem...show work please
Alona [7]
A) you must plug in 50 for variable F and solve for C

C=\frac{5}{9}(50-32)
C=\frac{5}{9}(18)
C= 10
50 degrees fahrenheit is equal to 10 degrees celsius 

B) you must solve the equation for F

C= \frac{5}{9}(F-32)
C/\frac{5}{9}=F-32
C/\frac{5}{9}+32=F
F= C/\frac{5}{9}+32

dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as

F=\frac{9}{5}C +32

now you just plug in 50 for the variable C in the new equation

F= \frac{9}{5}(50) +32
F= 90 + 32
F= 122

50 degrees celsius is equal to 122 degrees fahrenheit

hope this helped!

6 0
3 years ago
What is the simplest form of 8/28?
Marizza181 [45]
2/7 because both 8 and 28 are divisible by 4
5 0
3 years ago
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answers please asap for this question please i have been waiting for ever and its due tomorrow the 10th
ololo11 [35]
Hi there!

First, let's create an equation for the table: m = 2n + 40. Using this equation, we can find the values of x, y, and z.

WORK:
x = 2(4) + 40
x = 8 + 40
x = 48
y = 2(5) + 40
y = 10 + 40
y = 50
z = 2(6) + 40
z = 12 + 40
z = 52

Next, using the equation, we know that the initial investment would be 40, since that is the y-intercept of the equation. To express M in terms of N, that would be our equation m = 2n + 40. To find 10 years, we'll plug in 10 for n.

WORK:
m = 2(10) + 40
m = 20 + 40
m = 60 after 10 years

To figure out when his investment would double, we'll need to use 80 (double his initial investment of 40) in place of m.

WORK:
80 = 2n + 40
40 = 2n
n = 20 years


Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
7 0
3 years ago
Helllllpppppppppppppppppp
Bogdan [553]

The sum of the inner angles of a polygon with n sides is 180(n-2)

Since your polygon has 6 sides, the sum of its inner angles has to be

180(6-2) = 180 \cdot 4 = 720

On the other hand, the sum of its inner angles is

75+132+113+108+160+x = 588+x

And it has to be 720, so we have

588+x=720 \iff x = 720-588 = 132

7 0
3 years ago
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