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LekaFEV [45]
2 years ago
13

In , side is extended to point E. When connected to vertex A, segment is parallel to segment . In this construction, you are giv

en that bisects .
Prove:
Complete the paragraph proof.

A diagram of a triangle ABC. D is the midpoint of the base AC. A line connects BD. A dashed line AE and BE is drawn outside the triangle.

, since bisects and the two angles created on each side of the bisector at point B are equal. because of the corresponding angles theorem. because
. by the substitution property of equality. by the triangle proportionality theorem. If two angles in a triangle are congruent, the sides opposite the angles are congruent, so .
by the substitution property of equality.
Mathematics
1 answer:
givi [52]2 years ago
8 0
  1. Angle 1 is congruent to angle 2, since BD bisects <ABC and the two angles created on each side of the bisector at point B are equal.
  2. <2 ≅ <3 because of the corresponding angles theorem.
  3. <1 ≅ <4 because alternate angles are congruent if two parallel lines are cut by a transversal.
  4. <3 ≅ <4 by the substitution property of equality.
  5. AD/CD = EB/CB by the triangle proportionality theorem.
  6. If two angles in a triangle are congruent, the sides opposite the angles are congruent, so AE = EB.
  7. AD/CD = AB/CB by the substitution property of equality.

<h3>The properties of similar triangles.</h3>

In Geometry, two (2) triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

<h3>What is the substitution property of equality?</h3>

The substitution property of equality states that assuming x, y, and z are three (3) quantities, and if x is equal to y (x = y) based on a rule and y is equal to z (y = z) by the same rule, then, x and z (x = y) are equal to each other by the same rule.

In this context, we can reasonably infer and logically deduce that the ratio of AD/CD is equal to AB/CB based on the substitution property of equality.

Read more on substitution property here: brainly.com/question/2459140

#SPJ1

Complete Question:

In ΔABC, side BC is extended to point E. When connected to vertex A, segment EA is parallel to segment BD. In this construction, you are given that BD bisects <ABC.

Prove: AD/CD = AB/CB.

Complete the paragraph proof.

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Step-by-step explanation:

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8 0
3 years ago
You have 600 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river
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Answer:

The length and width of plot is L=300\:ft, W=150\:ft

Largest area of the plot is A=45000 ft^{2}

Step-by-step explanation:

Assume width as x and length as y. Given that length of fencing is 600 feet and fencing is enclosed on 3 sides. So perimeter is given as,

Perimeter = width + length + width

Substituting the value,  

600=x+y+x

600= 2x+y  ….1

Now area of fence of rectangular box is given as follows,  

A=xy  ….2

Solving equation 1 for y, subtracting 2x from both sides,  

600-2x= y

Substituting the value in equation 2,  

A=x\left (600-2x  \right )

Simplifying

A=600x-2x^{2}

Rewriting,  

A=-2x^{2}+600x

Above equation looks like quadratic equation f\left ( x \right )=ax^{2}+bx+c whose graph looks like parabola.  

Comparing equation f(x) and A values of a, b and c are, a=-2,b=600 and c=0.  

Now maximum of f\left ( x \right ) occurs at vertex.  

The x coordinate of the vertex is given as -\dfrac{b}{2a}

Substituting the values,  

x=-\dfrac{600}{2\left (-2  \right )}

Simplifying,  

x=\dfrac{600}{4}

x=150

So width of plot is 150 feet.  

Now to calculate value of length by using equation 1,

600= 2x+y

Substituting the values,

600= 2\left (150  \right )+y

600= 300+y

Subtracting 300 from both sides,

300= y

So length of plot is 300 ft.

The y coordinate of the vertex is given as y=f\left ( -\dfrac{b}{2a} \right ) which also means, y=f\left ( 150 \right )

\therefore A=-2\left (150  \right )^{2}+600\left (150  \right )

Simplifying,  

\therefore A=-2\left (22500  \right )^{2}+600\left (150  \right )

\therefore A=-45000+90000

\therefore A=45000

So, area of the plot will be A=45000 ft^{2}

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