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n200080 [17]
3 years ago
13

F(x) = 4x² + 19x – 5 What are the x intercepts

Mathematics
1 answer:
gogolik [260]3 years ago
7 0
Fix and 4x hhhhhhhhhhhhhhh
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Write the slope-intercept form of the linear equation that has a slope of 3
Goshia [24]

Answer:

y = 3x - 1

Step-by-step explanation:

Slope-intercept form: y = mx + b

m = slope

b = y-intercept

8 0
3 years ago
PLEASE! ANSWER THIS! HELP! PLEASE!!!!!!!!!!!!!! <br><br>c. Expand: (tan(theta) - 1)^3​
jonny [76]

Answer:

(tan(theta)-1)^3

= (tan(theta)-1)(tan(theta)-1)(tan(theta)-1)

= (tan^2(theta)-2tan(theta)+1)(tan(theta)-1)

= tan^3(theta)-2tan^2(theta)+tan(theta)-tan^2(theta)+2tan(theta)-1

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6 0
2 years ago
Find the midpoint on segment AB; A (0, 6), B (4, 2)
Bogdan [553]

Answer:

2,4

Explanation:

Because a midpoint is the middle of the line

8 0
3 years ago
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Of the 465 sophomores at eastside high school, exactly 13 are taking french ii or chemistry i or both. there are 40 sophomores t
gizmo_the_mogwai [7]
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8 0
3 years ago
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A rectangular park 40 yards wide was redesigned, and a path 1 yard wide was built around it. How long was the park before if, af
forsale [732]

Answer:

98 yards

Step-by-step explanation:

The new width is 40 yds + 2 yds = 42 yds.

Area = L × W

4200 square yds = L × 42 yds

L = 4200 yds ÷ 42 yds = 100 yds

The new length is 100 yds.

The old length = the new length - the width of the path × 2 = 100 yds - 1 yd × 2 = 100 yds - 2 yds = 98 yds.

The length of the park was 98 yds, before the path was built.

3 0
3 years ago
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