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2 years ago

15

Guys help me what is the answer?

1 answer:

Free_Kalibri [48]2 years ago

7 0

Step-by-step explanation:

C. represent the number line for x

where x ix

3x<u>></u>6
x<u>></u><u> </u>6/3
x<u>></u>2

<h2>hope it helps.</h2><h2>stay safe healthy and happy.</h2>

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A total of 1,650 boxes of Girl Scout cookies were sold last week. Each large box cost $3.50 and each small box cost $2.00. The G

s344n2d4d5 [400]

Answer:

900 large boxes were sold, and 750 small boxes.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of large boxes of cookies sold.

y is the number of small boxes of cookies sold.

A total of 1,650 boxes of Girl Scout cookies were sold last week.

This means that

$x + y = 1650$

So

$x = 1650 - y$

Each large box cost $3.50 and each small box cost $2.00. The Girl Scout group earned $4,650.

This means that

$3.5x + 2y = 4650$

Since $x = 1650 - y$

$3.5(1650 - y) + 2y = 4650$

$5775 - 3.5y + 2y = 4650$

$1.5y = 1125$

$y = \frac{1125}{1.5}$

$y = 750$

$x = 1650 - y = 1650 - 750 = 900$

900 large boxes were sold, and 750 small boxes.

8 0

2 years ago

What is the area of this figure

Dimas [21]

Cut the figure into two parts
area of a rectangle is length x width
10x5=50m
2x4=8
add them together
50+8=58

4 0

2 years ago

a recent survey determained that 7 out of 9 students eat school lunch at least once a week. if 54 students were surveyed how man

Setler [38]

Answer:

12 students

Step-by-step explanation:

Given

$Students = 54$

Required

Determine the number of students that eat lunch once a week

In Sets;

If out of 9, at least 7 eats one a week then

9 - 7 eats lunch once a week

$9 - 7 = 2$

<em>In other words;</em>

2 out of 9 students eat lunch once a week

Number of students in this category is then calculated as thus;

$Number = \frac{2}{9} * 54$

$Number = \frac{2 * 54}{9}$

$Number = \frac{108}{9}$

$Number = 12$

3 0

3 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

Read 2 more answers

Solve 2(x-3)>-3(-3+x)<br><br> (Picture added, multiple choice)

Rudiy27

Answer:

<u>Answer</u><u>:</u><u> </u><u>D</u>

Step-by-step explanation:

$2(x - 3) \geqslant - 3( - 3 + x)$

open the brackets [ distributive property ]

$2x - 6 \geqslant 9 - 3x$

collect like terms:

$2x + 3x \geqslant 9 + 6 \\ 5x \geqslant 15$

divide either sides by 5:

$\frac{5x}{5} \geqslant \frac{15}{5} \\ \\ { \underline{ \bf{ \: \: x \geqslant 3 \: \: }}}$

3 0

2 years ago