Answer:
w = -1.44 and w = -14.06
Step-by-step explanation:
That "(3) / (4)" in (w+14)/(4w+6)=(3)/(4) looks fishy. Assuming that you really meant 3/4, then we have (w+14)/(4w+6)=3/4.
Mult. both sides by 4 to remove the fraction: 4(w+14)/(4w+6) = 3.
Multiply out (w+14)/(4w+6): 4w^2 + 6w + 56w + 84. Combine the w terms, obtaining 4w^2 + 62w + 84. Then the original equation becomes:
4w^2 + 62w + 84 = 3, or 4w^2 + 62w + 81 = 0.
This is a quadratic equation, with a = 4, b = 62 and c = 81. The two roots (values of
w) are as follows:
-62 plus or minus √(62^2-4(4)(81)
----------------------------------------------------------
8
-62 plus or minus √(2548) -62 plus or minus 50.48
w = ------------------------------------------- = ---------------------------------------
8 8
Simplifying, we get w = -1.44 and w = -14.06
Well first take 1 die the chance of getting odd is 1/2 now the 2nd die is also 1/2 so what you do from now is multiply them 1/2*1/2=1/4
You have a 1/4 chance of both dice showing an odd number
Answer:
3.67 hours
Step-by-step explanation:
Speed is the ratio of distance to time, it is given by the formula:
Speed = Distance / time
For annike her average speed was 11 miles per hour and she started at 7 am.
At 8 am (time = 1 hr i.e 7 am to 8 am) the distance she would have covered is given as:
11 miles/hr = distance / 1 hr
Distance = 11 miles per hr × 1 hr = 11 miles
After 8 am, the distance traveled at time t is:
11 = distance/t
distance = 11t
Total distance = 11t + 11
For Celia she started at 8 am at 14 miles per hour, at time t, the distance traveled is:
14 = distance/t
Distance = 14t
Given that both bikers traveled the same distance, hence:
14t = 11t + 11
3t = 11
t = 11/3
t = 3.67 hours
<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
Answer:
I can't see
Step-by-step explanation:
do you mind zooming in
